Assuming an initial velocity of about 2500 ft/s.
2006-07-20 14:59:34 · 11 answers · asked by scb572 1 in Science & Mathematics ➔ Physics
To make the question more specific, let's say the bullet is a .22 caliber fired at 2500 ft/s vertically. Would that help?
2006-07-20 15:36:59 · update #1
This is my friends acount and he thinks it will easily hit 30,000 feet. I think it would be around a little over 1 mile.
2006-07-20 15:38:21 · update #2
It depends on the angle that you have fired and also the type of distance you wanted to calculate.
Hope you understand the problem. So please specify those also. Then contact me.
2006-07-20 15:12:14 · answer #1 · answered by Sherlock Holmes 6 · 0⤊ 1⤋
This is only a guess, but...
In the military we were told that our 7.62mm M-14s had an absolute range of about 7 miles if fired at a 45-deg angle. That puts the peak around 2 miles. I'd guess that fired straight up would be a bit higher, maybe in the 3-4 mile range.
(By the way, I hope you're not going to try to take pot-shots at passing airliners...)
2006-07-20 22:24:11 · answer #2 · answered by Eric 5 · 0⤊ 0⤋
2500 fps is a bit fast for a 22, its closer to 1000 fps. anyway, at 32 fps deceleration, the bullet stops going up in 30 seconds. 500 feet x 30 comes to about 15,000 feet, or three miles. oh, the reason you use 500, is thats the average speed of the bullet
2006-07-20 23:30:55 · answer #3 · answered by iberius 4 · 0⤊ 0⤋
The average .22 cal. high velocity round Will travel about 1 mile in good weather but if it is traveling up the law of gravity will greatly slow it and it will not reach anywhere near a mile. Maybe about 1/8 of a mile in perfect conditions.
2006-07-20 23:14:52 · answer #4 · answered by ? 3 · 0⤊ 0⤋
Neglecting air resistance, the height through which the bullet can go is given by the formula,
H = (U^2) / 2g, 2500 x2500 / 2x 32.
That is 18.5 miles.
But in practice, since air resistance is very high, the actual height is very low.
2006-07-20 22:21:27 · answer #5 · answered by Pearlsawme 7 · 0⤊ 0⤋
The answer will be much easier if you assume a vacuum; that's a simple math problem involving /_\S = Vi/_\T + 1/2(A/_\T^2)
However, in air (and aren't we all in air, after all?) it's a more difficult question due to drag. For large caliber rounds, several thousand feet would be expected. Think 3,000 to 4,000 and possibly more for heavier rounds like .50 cal.
2006-07-20 22:06:27 · answer #6 · answered by Anonymous · 0⤊ 0⤋
IT DEPENDS! There are a lot of variables to consider, like how much powder did you put in that bullet, how heavy is that bullet, how hard is the wind blowing, how tall are you, etc.
Let me know when you decide to fire this experiment, I want to be sure I'm up wind.
I hope you like this NOVA answer I don't know any ten dollar words, only five dollar words like variable.
2006-07-20 22:30:49 · answer #7 · answered by Anonymous · 0⤊ 0⤋
about 1 mile
2006-07-20 22:02:57 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Depends on the caliber of the bullet and the amount and type of powder in the cartridge.
2006-07-20 22:06:51 · answer #9 · answered by coffeebean 2 · 0⤊ 0⤋
In a vacuum, I would agree in the 18.5 miles up, but this is obviously wrong.
This web page may be of help.
2006-07-20 23:07:43 · answer #10 · answered by a simple man 6 · 0⤊ 0⤋