English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Solve for x 3x^2 = 48 I got 3(x+4)(x-4) 3=0, x=4 x=-4 is this right and if not could you answer this in detail thanks!

2006-07-20 13:28:44 · 14 answers · asked by michael b 1 in Science & Mathematics Mathematics

14 answers

Yes it is correct and there is another method also.

It is as follows.

3x^2 = 48
gives x^2 = 16
implies x = 4, -4 (Plus or minus 4)

It is both 4 and -4 as the squares of both the numbers is the same thing i.e., 16.

Your method is also the correct one.

Hope you had understood the other method also.

2006-07-20 14:40:05 · answer #1 · answered by Sherlock Holmes 6 · 0 0

3x^2=48
=>1/3*3 X^2=48*1/3
=>x^2=16
and take both sides under squarehood
x=-4, or +4
and yes ur answer is right
well done

2006-07-20 16:01:43 · answer #2 · answered by melb 1 · 0 0

3x^2=48
divide by 3 on each side
48/3= 16 now find the square root of 16
16 is perfect square so 4*4=16
x=4 or x=-4
since -*-=positive
+*+=positive then 3(4)^2=48
=3(16)=48
3(-4)^2 = 3(16)=48

2006-07-20 13:42:18 · answer #3 · answered by ? 2 · 0 0

X=4,-4 It has two answers. Try running it in reverse. Divide 48 by 3 = 16. So the Square of 16 is, anyone, anyone...4.

But!

All real roots have two answers, + and -. So the TWO answers are 4 and -4. But from now on, look it up, and do your own work.

2006-07-20 13:30:56 · answer #4 · answered by Anonymous · 0 0

Quadratic formulation is: x = -b +- ?b^2 - 4ac / 2a 3x^2 + 12x = -4 upload 4 to the two aspects. 3x^2 + 12x + 4 = 0 ax^2 + bx + c = 0 a = 3 b = 12 c = 4 -12 +- ?12^2 - 4(3)(4) / 2(3) = -12 +- ?a hundred and forty four - 40 8 / 6 = -12 +- ?ninety six / 6 = -12 +- 4?6 / 6 = -2 +- 4?6 x = -2 - 4?6 x= -2 + 4?6

2016-11-02 10:40:24 · answer #5 · answered by pachter 4 · 0 0

Don't Forget you could use the quadratic formula on this as well.

Let a = 3 , b = 0 and c = -48 or let a = 1, b = 0, and c = -16

you still get 4, -4

2006-07-20 14:01:25 · answer #6 · answered by msmath 1 · 0 0

yes, x = 4, -4...period.
since 3 can not = 0, that is not part of the answer

another way to solve is to divide both sides by 3 and then take the square root of both sides...16 has 2 square roots, 4 and -4, giving the same answer as factor, which was your method

2006-07-20 13:37:01 · answer #7 · answered by matt the math teacher 2 · 0 0

here is an easier way to do this

3x^2 = 48
x^2 = (48/3)
x^2 = 16
x = 4 or -4

2006-07-20 14:34:05 · answer #8 · answered by Sherman81 6 · 0 0

You factored the equation as 3(x+4)(x-4) = 0... Setting each of the factors equal to zero you obtained x = 4, x = -4 as your two solutions.

Looks right... Congratulations. You didn't settle for the "taking the square root of each side" garbage that so many others try.

2006-07-20 13:34:27 · answer #9 · answered by AnyMouse 3 · 0 0

3x^2=48
x^2=48/3 or 16
x=square root of 16
x=4 or -4

2006-07-20 16:14:13 · answer #10 · answered by Anonymous · 0 0

fedest.com, questions and answers