Yes it is correct and there is another method also.
It is as follows.
3x^2 = 48
gives x^2 = 16
implies x = 4, -4 (Plus or minus 4)
It is both 4 and -4 as the squares of both the numbers is the same thing i.e., 16.
Your method is also the correct one.
Hope you had understood the other method also.
2006-07-20 14:40:05
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answer #1
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answered by Sherlock Holmes 6
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3x^2=48
=>1/3*3 X^2=48*1/3
=>x^2=16
and take both sides under squarehood
x=-4, or +4
and yes ur answer is right
well done
2006-07-20 16:01:43
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answer #2
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answered by melb 1
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3x^2=48
divide by 3 on each side
48/3= 16 now find the square root of 16
16 is perfect square so 4*4=16
x=4 or x=-4
since -*-=positive
+*+=positive then 3(4)^2=48
=3(16)=48
3(-4)^2 = 3(16)=48
2006-07-20 13:42:18
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answer #3
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answered by ? 2
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X=4,-4 It has two answers. Try running it in reverse. Divide 48 by 3 = 16. So the Square of 16 is, anyone, anyone...4.
But!
All real roots have two answers, + and -. So the TWO answers are 4 and -4. But from now on, look it up, and do your own work.
2006-07-20 13:30:56
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answer #4
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answered by Anonymous
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Quadratic formulation is: x = -b +- ?b^2 - 4ac / 2a 3x^2 + 12x = -4 upload 4 to the two aspects. 3x^2 + 12x + 4 = 0 ax^2 + bx + c = 0 a = 3 b = 12 c = 4 -12 +- ?12^2 - 4(3)(4) / 2(3) = -12 +- ?a hundred and forty four - 40 8 / 6 = -12 +- ?ninety six / 6 = -12 +- 4?6 / 6 = -2 +- 4?6 x = -2 - 4?6 x= -2 + 4?6
2016-11-02 10:40:24
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answer #5
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answered by pachter 4
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Don't Forget you could use the quadratic formula on this as well.
Let a = 3 , b = 0 and c = -48 or let a = 1, b = 0, and c = -16
you still get 4, -4
2006-07-20 14:01:25
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answer #6
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answered by msmath 1
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yes, x = 4, -4...period.
since 3 can not = 0, that is not part of the answer
another way to solve is to divide both sides by 3 and then take the square root of both sides...16 has 2 square roots, 4 and -4, giving the same answer as factor, which was your method
2006-07-20 13:37:01
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answer #7
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answered by matt the math teacher 2
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here is an easier way to do this
3x^2 = 48
x^2 = (48/3)
x^2 = 16
x = 4 or -4
2006-07-20 14:34:05
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answer #8
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answered by Sherman81 6
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You factored the equation as 3(x+4)(x-4) = 0... Setting each of the factors equal to zero you obtained x = 4, x = -4 as your two solutions.
Looks right... Congratulations. You didn't settle for the "taking the square root of each side" garbage that so many others try.
2006-07-20 13:34:27
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answer #9
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answered by AnyMouse 3
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3x^2=48
x^2=48/3 or 16
x=square root of 16
x=4 or -4
2006-07-20 16:14:13
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answer #10
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answered by Anonymous
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