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x <= 5 and x <= -1

2006-07-20 07:24:37 · 8 answers · asked by Brandon ツ 3 in Science & Mathematics Mathematics

8 answers

since anything below -1 counts for everything below 5, the only thing that really matters is x <= -1

(-infinity,-1]

2006-07-20 14:57:53 · answer #1 · answered by Sherman81 6 · 1 3

Again, an "and" statement means that BOTH conditions MUST be true.
Numbers less than or equal to -1 satisfy both inequalities. Numbers between -1 and 5 satisfy one (x ≤ 5), but not both.

The correct solution set is x in the interval
(-∞, -1].

2006-07-20 07:39:52 · answer #2 · answered by Louise 5 · 0 0

If x<=5 and x<=-1, it means that x is obviously less than -1.
If x is real, then
x belongs to (-infinity,-1]

If you have made a mistake in the question, i.e.
if x<=5 and x>=-1, then x belongs to [-1,5]

or if x>=5 and x<=-1, then
x belongs to (-infinity,-1]U[5,+infinity)

Note that for all the above cases, x is real.
Hope the answer helps.

2006-07-20 07:31:54 · answer #3 · answered by ankit41 3 · 0 0

x ≤ -1. Any number that's ≤ -1 is also ≤ 5.

So the answer is {x | x ≤ -1}., or (-∞, -1]...

ankit is right. If you really meant "x ≥ 5" instead of "x ≤ 5", then the answer would be (-∞, -1]U[5, ∞)... or it could be written as {x | x ≥ 5 || x ≤ -1}, where || is the "or" command.

the "or" command isn't really written that way in math... but I just wrote it that way.

2006-07-20 07:52:35 · answer #4 · answered by Anonymous · 0 0

first i think u typed it in wrong x is less than or equal to 5 includes x is less than or equal to -1. i think u meant x<=5 and x>=-1 which would be -1<=x<=5

2006-07-20 09:12:01 · answer #5 · answered by bigdog2all2 1 · 0 0

x c- (-infinity, 5]

2006-07-20 07:27:53 · answer #6 · answered by shyam 2 · 0 0

(-∞,-1]
is your answer

2006-07-20 07:30:52 · answer #7 · answered by Anonymous · 0 0

(0, infinity)
AND...I'm guesing!

2006-07-20 07:47:30 · answer #8 · answered by Anonymous · 0 0

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