since anything below -1 counts for everything below 5, the only thing that really matters is x <= -1
(-infinity,-1]
2006-07-20 14:57:53
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answer #1
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answered by Sherman81 6
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Again, an "and" statement means that BOTH conditions MUST be true.
Numbers less than or equal to -1 satisfy both inequalities. Numbers between -1 and 5 satisfy one (x ⤠5), but not both.
The correct solution set is x in the interval
(-â, -1].
2006-07-20 07:39:52
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answer #2
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answered by Louise 5
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If x<=5 and x<=-1, it means that x is obviously less than -1.
If x is real, then
x belongs to (-infinity,-1]
If you have made a mistake in the question, i.e.
if x<=5 and x>=-1, then x belongs to [-1,5]
or if x>=5 and x<=-1, then
x belongs to (-infinity,-1]U[5,+infinity)
Note that for all the above cases, x is real.
Hope the answer helps.
2006-07-20 07:31:54
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answer #3
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answered by ankit41 3
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x ⤠-1. Any number that's ⤠-1 is also ⤠5.
So the answer is {x | x ⤠-1}., or (-â, -1]...
ankit is right. If you really meant "x ⥠5" instead of "x ⤠5", then the answer would be (-â, -1]U[5, â)... or it could be written as {x | x ⥠5 || x ⤠-1}, where || is the "or" command.
the "or" command isn't really written that way in math... but I just wrote it that way.
2006-07-20 07:52:35
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answer #4
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answered by Anonymous
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first i think u typed it in wrong x is less than or equal to 5 includes x is less than or equal to -1. i think u meant x<=5 and x>=-1 which would be -1<=x<=5
2006-07-20 09:12:01
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answer #5
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answered by bigdog2all2 1
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x c- (-infinity, 5]
2006-07-20 07:27:53
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answer #6
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answered by shyam 2
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(-â,-1]
is your answer
2006-07-20 07:30:52
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answer #7
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answered by Anonymous
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(0, infinity)
AND...I'm guesing!
2006-07-20 07:47:30
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answer #8
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answered by Anonymous
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