2006-07-20 03:09:20 · 6 answers · asked by JR 1 in Sports ➔ Baseball
It's under Rule 10.0.4 b of the MLB rules:
http://mlb.mlb.com/NASApp/mlb/mlb/official_info/official_rules/official_scorer_10.jsp
I'm guessing that the reason why you don't get an RBI has to do with the fact that you've made 2 outs on the play where you've driven in the run. In a case like that, I guess you simply don't deserve the RBI. It's a matter of opinion, but I like the rule.
2006-07-20 03:16:13 · answer #1 · answered by Craig S 7 · 2⤊ 0⤋
The answer is because it was an easy infield groundball. If the run really mattered which would be what they call a 'productive run' (which would be marked as an RBI) the infielder would have thrown it home. Rather, the defense figured since the run wasn't important, they'd get two outs over one.
2006-07-20 13:39:43 · answer #2 · answered by Caesar 2 · 0⤊ 0⤋
i think it's sort of like a forced-run, fielder's choice type deal. it's not considered an RBI because i think it's up to the runner on 3rd to score or not, and up to the fielders as to if they'd rather get 2 outs with letting the run score.
2006-07-20 17:24:04 · answer #3 · answered by public_spirited 2 · 0⤊ 0⤋
Probably because the batter a) hit a ground ball to the infield and b) caused two outs. The scoring logic is that he did little to nothing to get the run in (versus hitting a sac fly, which isn't that difficult).
2006-07-20 10:13:53 · answer #4 · answered by Anonymous · 0⤊ 0⤋
There just isn't. I think an exception should be made when it's a walk-off run, though.
2006-07-20 10:13:09 · answer #5 · answered by wmp55 6 · 0⤊ 0⤋
no clue
2006-07-20 10:36:04 · answer #6 · answered by Anonymous · 0⤊ 0⤋