you add the two equations.
0.7 of roses and 0.7 of carnations is equal to 91.
roses and carnations is equal to 91/7 or 13.
there! no algebra... =)
2006-07-20 04:12:17
·
answer #1
·
answered by Em 5
·
1⤊
0⤋
What you are saying is, there are 38 flowers in a group, made up of roses and carnations.
Then there are 53 flowers in a group, made up of roses and carnations.
.0.2 and 0.5 are percentages or a fraction of the total.
0.2 = 2/10 and 0.5 =5/10
Think for a moment, do the two percentages, 0.2 plus 0.5 =0.10 or do they total to, 100% of the group, or just the total of roses and carnations? Are there other flowers not mentioned?
Is 38 all the flowers. Is 53 all the flowers. Or are the roses and carnations only a part of the total, not given?
So, you do know that 0.2 plus .05 = ???? The given totals.
Now always remember one thing. In basic arithmetic, there are only four things you can do.
Thinking of the above problem.
Do you add?
Do you subtract?
Do you divide?
Do you multiply?
Which method would you use to find how many roses and how many carnations total 38 or 53?
If II have a pizza and you can take 0.5 or 0.2 parts of it, and it was already cut into 10 slices, how many pieces can you take as 0.5 or 0.2?
Hope this helps you solve it.
2006-07-20 01:41:18
·
answer #2
·
answered by ed 7
·
0⤊
0⤋
Designation of x and y
x = rose
y = carnation
Value of x and y
X = 0.5
y = 0.2
Equation 1
0,5x + o.2y = 38
Equation 2
0.2x + 0.5y = 53
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
System of Equations, The substitute Method
1). 0.5x + 0.2Y = 38
2). ).2X + 0.5Y = 53
Using 0.5X + 0.2Y = 38 for the substitution in equation 1
0.5X + 0.2 y = 38
-0.5x -0.5x
Subtract -0.5x from both sides
0.2y = 38 - 0.5x
0.2 Y/0,2 = 38 - 0.5x/0,2
divide 0.2 from both sides
y = 190 - 2.5x
0.5x + 0.2(190 - 2.5x) = 38
Substitute 190-2.5x into the y position in equation 2
.02x + 0.5(190-2.5x) = 53
0,2x + 95 - 1.25x = 53
The distribtive property
0.2x + 95 - 1.25x = 53
- 53 -53
subtract 53 from both sides
0.2x + 42 -1.25x = 0
-1.05x + 42 = 0
+1.05x +1.05
add 105x to both sides
42 = 1.05x
42/1.05 = 1.05x/1.05
Divide 1.05 from both sides
40 = x
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
0,2x + 0,5y = 53
0.2(40) + 0.5y = 53
substitute 40 into the x position and multiply .2 x 40 = 8
8 + 0.5y = 53
-8 -8
subtract 8 from both sides
0.5y = 45
0.5y/0.5 = 8/0,5
Divide 0.5 from both sides
y = 90
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
Check Equation 1
X = 40
y = 90
0.5x + 0.2y = 38
0.5(40) + 0.2(90) = 38
Substitute 40 and 90 into the x and y positions
20 + 18 = 38
38 = 38
There are 40 roses and 90 carnations
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
Check Equation 2
x = 40
y = 90
0.2x + 0.5y = 53
0,2(40) + 0.5(90) = 53
8 + 45 = 53
53 = 53
There are 40 roses and 90 Carnations
2006-07-20 04:13:19
·
answer #3
·
answered by SAMUEL D 7
·
0⤊
0⤋
The answers are:
40 roses
90 carnations
130 overall
I am afraid there is no simple way of either solving it or proving it without the use of algebra. You will probably not understand this since you are in primary school but here is the proof:
1) Let's say that the number of roses is x and the number of carnations is y.
2) Form two equations
a) 0.5x + 0.2y = 38 b) 0.2x + 0.5y = 53
3) Simplify your equations by multiplying by ten
a) 5x + 2y = 380 b) 2x + 5y = 530
4) Now here comes the difficult part: substitution
Take one of the equations for example the first one and make y the subject of the formula:
2y = 380 - 5x
y = 190 - 2.5x
Now you have expressed y in terms of x.
Wherever you see y in your second equation, put the equation you have just created.
So now you have just one equation:
2x + 5(190 - 2.5x) = 530
5) Simplify your equation by expanding the bracket:
2x + 950 - 12.5x = 530
- 10.5x = - 420
10.5x = 420
x=420/10.5 = 40
6) We have found x = 40 the number of roses. Now all you have to do is put that number in either of the two equations to get y, the number of carnations.
0.5 * 40 + 0.2y = 38
20 + 0.2y = 38
0.2y = 18
y = 90
7) The roses are 40 the carnations are 90, now all you have to do is add them:
40 + 90 = 130
I hope I have helped :)
2006-07-20 01:42:43
·
answer #4
·
answered by pink_musicgirl 2
·
0⤊
0⤋
break it down
Let x = roses
Let y = carnations
0.5x + 0.2y = 38
0.2x + 0.5y = 53
try reduction
0.5* ( 0.5x + 0.2y = 38 ) >>> 2.5x + 1.0y = 190
0.2* ( 0.2x + 0.5y = 53 ) >>> 0.4x + 1.0y = 53
Subtract "y" cancel
2.1x + 0y = 84 >>> 2.1x = 84 >>> x = 40
Substitute x now = 40 into the original equation
0.5(40) + 0.2y = 38 >>> 20 + 0.2y = 38
0.2y = 38 - 20 >>> 0.2y = 18
y = 18/0.2 >>> y = 90
Now we have "x" and "y" substitute both values into the equation. if the left side = the right side, you just proofed the equation.
Now I how you have a better understanding for your summer school.
2006-07-20 01:21:53
·
answer #5
·
answered by Juggernaut 3
·
0⤊
0⤋
Denote rose by r and carnations by c.
Then from 1st condition of the problem:
0.5r + 0.2c = 38 ...(i)
0.2r + 0.5c = 53 ...(ii)
Divide (i) on both sides by 0.5, we have:
r + 0.4c = 76 ...(iii)
Divide (ii) on both sides by 0.2, we have:
r + 2.5c= 265 ...(iv)
Subtract (iii) from (iv) to obtain:
(r+2.5c) - (r+0.4c) = 265-76
or, (2.5-0.4)c = 189
or 2.1c = 189
or c = 189/2.1
or c=90
Substituting this value of c in (iv), we have,
r + 2.5(90) = 265
or r + 225 = 265
or r= 265-225
or r=40
Thus, r=40 and c= 90.
Answer to this question is:
total number of roses are 40 and the number of carnations are 90.
2006-07-20 01:20:18
·
answer #6
·
answered by StreetX 2
·
0⤊
0⤋
If you got an answer by calculating it you would not have any trouble proving it.
Anyway:
multiply everything in the first equation by 2:
r+ 0.4 car = 76
multiply the second one by 5:
r+2.5 car = 265
subtract the first one from the second.
2.1 car = 189
189/2.1= 90
carnations = 90
substitute this number into the second equation to get this:
0.2 r + 45 = 53
0.2r = 8
r = 40
total number is 130
If you are having trouble understanding decimals transform them into fractions.
The amount of algebra you need to understand this is minimal.
2006-07-20 01:21:43
·
answer #7
·
answered by inw99 2
·
0⤊
0⤋
x - rose
y - carnations
(1) 0.5x + 0.2y = 38
(2) 0.2x + 0.5y = 53
(1) 0.2y = 38 - 0.5x
0.1y = 19 - 0.25x
(2) 0.2x + 95 - 1.25x = 53
42 = 1.05x
x = 40
(1) 0.1y = 19 - 0.25*40
0.1y = 9
y = 90
Good luck at school
2006-07-20 01:21:30
·
answer #8
·
answered by anni_shaa Yeap Yip 3
·
0⤊
0⤋
.5 0f rose and .2 of carnations=38
5 rose and 2 carnations=380
10 rose and 4 carnations=760..................(1)
.2 rose and .5 carnations=53
2 rose and 5 carnations=530
10 rose and 25 carnations=2650.................(2)
comparing (1) and (2)
21 carnations=1890
1 carnation=90 1rose=40
2006-07-20 02:25:01
·
answer #9
·
answered by raj 7
·
0⤊
0⤋
That's a simultaneous equation. I had to do it out to see what it was so I'll give you the answer and the method..... Heck, dude, I'm not putting in that much time. You're doing this at primary school? Are they some kind of imbeciles? the ancient Greeks gave us the best method off teaching and you start kids of slow.
btw, street is right. I just checked his/her answer. Checking is easy, just 10 secs.
2006-07-20 01:09:02
·
answer #10
·
answered by smile 3
·
0⤊
0⤋