How many angles would a regular polygon have if each exterior angle measures 5°?
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2006-07-19 21:03:58 · 10 answers · asked by Zman 1 in Science & Mathematics ➔ Mathematics
Since the total of the exterior angles must be 360 degrees, you can divide 360 by 5 to get 72 sides.
2006-07-19 21:13:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
if exterior angle measures 5 degrees, then the corresponding interior angle would be 275 degrees {360-(5+180)}. it's impossible for a polygon to have an exterior angle of 5 degrees
2006-07-19 21:12:36 · answer #2 · answered by saurabh k 2 · 0⤊ 0⤋
exterior angle * no. of sides =360°
so just pitching in the values the result is 72
2006-07-19 23:10:21 · answer #3 · answered by williamair1 2 · 0⤊ 0⤋
if external angle = 5 degrees this implies
number of sides will be 360/5 = 72, and so number of angles will be 71.
2006-07-19 21:55:00 · answer #4 · answered by ee r 1 · 0⤊ 0⤋
interior angle=180-5=175
=180-(360/n)
where n=number of side,ie number of angels
then number of angels=360/5=72 angels
2006-07-19 21:43:46 · answer #5 · answered by mohamed.kapci 3 · 0⤊ 0⤋
5 = 360/n
n = 360/5
n = 72
2006-07-20 03:47:50 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
8->
2006-07-19 21:08:47 · answer #7 · answered by question bank 1 · 0⤊ 0⤋
Theres no such thing as a "regular" polygon. Be more specific!!
2006-07-19 21:09:10 · answer #8 · answered by Anonymous 2 · 0⤊ 0⤋
73 ANGLES 74 SIDES
2006-07-19 21:08:33 · answer #9 · answered by conflict_management 2 · 0⤊ 0⤋
A lot.
2006-07-19 23:22:31 · answer #10 · answered by Anonymous · 0⤊ 0⤋