The distance from Philadelphia to Sea Isle City is 100 mi. A car was driven this
distance using tires with a radius of 14 in. How many revolutions of each tire
occurred on the trip?
Could someone please explain to me how to get the answer. I know it is 72, 000 revolutions, but how do I get this answer?
2006-07-19 20:08:26 · 6 answers · asked by Rene 5 in Education & Reference ➔ Homework Help
100 miles = 100*5280*12 inches = 63,360
14in radius = 28in diameter
circumference = 28pi
rotations = 6,336,000/28pi
2006-07-20 05:10:34 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Distance = one hundred mi Radius = 14 in discover the circumference of the tire. C = 2 * pi * r C = 2 * pi * (14 in) C = 40 3.ninety 8 in Convert your one hundred miles to inches supplies 6,336,000 inches. Divide your distance in inches by using your circumference in inches (as a results of the indisputable fact that could represent one revolution in accordance to circumference). kind of revolutions = 140 four,058
2016-10-14 23:53:31 · answer #2 · answered by mccarty 4 · 0⤊ 0⤋
I'll give you the simplest right answer, I am a year 8 and currently doing this stuff now.
Well start of with your radius is (2xpiex14) and then the answer of that times it by 100. Easy
I hoped this helped you.
Kind Regards, Timothy H.
2006-07-19 22:54:42 · answer #3 · answered by Timmy + Info = What You Need 2 · 0⤊ 0⤋
the circumference of the tyre is given by, c = 2*(22/7)*r. where r is radius.
now that give cirumference 'c' in inches.
total distance in mile is 100. 1 mile equals 63,360 inches. hence total distance in inches, d = 6336000 in.
hence, no. of revolutions, n = d/c.
do the calulations urself.
2006-07-19 21:41:23 · answer #4 · answered by Anonymous · 0⤊ 0⤋
use the radius to find the circumference of the tire in inches
then convert 100 miles to inches, and divide that by the circumference
2006-07-19 20:18:26 · answer #5 · answered by Shawn 3 · 0⤊ 0⤋
THAT'S EASY, iT'S 72'-80=61=,r==44]k37856to the 3rd power.
2006-07-19 20:51:51 · answer #6 · answered by Anonymous · 0⤊ 0⤋