Math help Rational Expressions?

Question

It says to solve: 1/x-2 + 1-x+2= 4/x^2-4 Then it also says state the excluded values. Please help me, I am terrible in Math.

Sorry it was supposed to be: 1/x-2 + 1/x+2 = x^2-4

Answer 1

why don't you do your homework yourself?

by the way, the way you wrote it, we have to read
1/x +1/x +2 -2 = 4/x² - 4
is that what you meant?

Answer 2

Edit: you changed it. is it 4/(x^2 -4) or x^2-4?

Multiply through by x^2-4 = (x+2)(x-2) which gives:

(x+2) + (x-2) = 4. So

2x = 4 and x = 2

In your original equation the values x= 2 and x = -2 are the excluded values since 1/(2-2) and 1/(-2+2) = 1/0, and division by 0 is undefined.

Answer 3

here i'll show you
=1/(x-2)+1/(x+2)=x^2-4
=1(x+2)/(x+2)(x-2)+1(X-2)/(x+2)(X-2)=(x+2)(x-2)/(x+2)(x-2)
=x+2+x-2=1
=2x=1
=x=1/2
as you can see i factored out X^2-4 because it is a perfect square and its simplified form is (x-2)(x+2) the i just have to get the GCf or greatest common factor then its just like normal division except that i sfactored out x^2-4 and changed it to (x-2)(x+2) because (x-2)(x+2) when you multiplied them it becomes X^2-4 so i simplified it so that i can cancel it out that's why it became 1 its like 2/2= 1 right? there i hope its helps with your math problems