Small cube, large cube determing difference?

Question

A small cube is x units per side. A large cube is (x + 2) units per side. What is an equation for a difference in their volume?

ex: 4x^2 + 8x + 8

Answer 1

Volume of large cube = (x+2)^3
Volume of small cube = x^3

(x+2)^3 - x^3 = 6x^2 + 12x +8

Answer 2

The volume of large cube is (x+2)^3
The volume of the small cube is x^
hence the difference is just (x+2)^3 - x^3
i.e
6x^2+12x+8

Answer 3

volume of large cube is
(x + 2)^3 = x^3 + 6x^2 + 12x + 8

volume of small cube is x^3

difference:
6x^2 + 12x + 8

Answer 4

We can use the identity for difference in volume.
(x+2)^3 - x^3 = [(x+2) - x][(x+2)^2 + x(x+2) + x^2]
(x+2)^3 - x^3 = [x + 2 - x][(x+2)^2 + x(x+2) + x^2]
(x+2)^3 - x^3 = (2)(x^2 + 4x + 4 + x^2 + 2x + x^2)
(x+2)^3 - x^3 = 2(3x^2 + 6x + 4)
The simplified equation is 2(3x^2 + 6x + 4).
Klo-Jann
** 3x^2=3(x^2)
This is the revised answer.

Answer 5

Your answer is A and D. in case you're taking the quantity of the first block you get a answer say 5m^3. ( in basic terms to make it undemanding I grant you with the given answer). So in case you positioned 8 of those(5m^3) blocks next to one yet another (8 circumstances 5m^3= 40m^3) the quantity of the great brick will be 8 circumstances the dimensions of the small block so as that states that the facet and the coolest surfaces of the small block is one-eighth the dimensions of the bigger block. And vice versa the bigger block is a 8 circumstances larger than the smaller block. wish you recognize now.