1600 ml of a gas @ 127Celsius and 900 torr would occupy what volume @ 27 C and 5000 torr?

Answer 1

P1*V1/T1 = P2*V2/T2

but T must be measured in °K, where 0°C = 273.16°K, so

(900 torr)*(1600 ml)/(127 + 273) = (5000 torr)*V2/(27 + 273)

or,

(900)*(1600 ml)*(300)/(5000*400) = V2 = 216 ml

Answer 2

9.2 x 10^ -5 mL

You can use PV = nRT (you don't need to factor in R though, because it'll end up cancelling out), and you don't need to change units because they're consistant.

Solve for n (number of moles of the gas), then use the second parameters and solve for the volume.