(0,4) and (2,1)
2006-07-19 13:52:58
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answer #1
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answered by coolio 3
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y=-2x +4 when x is 0, y is 4; so (0, 4)
when x is 1, y is -2; so (1, -2)
when x is 4, y is -4 ; so (4, -4)
put the points at (0,4) (1, -2) (4, -4)
Why r u asking all this questions anyway...u should be doing your homework all by yourself.
2006-07-19 14:08:19
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answer #2
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answered by Shyne_06 4
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In 2x + y = 4, give different values to x and you get values for y
eg: put x = 0, you get y = 4, the point is (0,4)
put x = 1, you get y = 2, the point is (1,2)
put x = 2, you get y = 0, the point is (2,0)
the points on the graph will be (0,4), (1,2) and (2,0)
2006-07-19 16:45:25
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answer #3
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answered by Subhash G 2
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Find x- and y-intercepts:
When x = 0, y = 4
When y = 0, x = 2
Draw a line through the points (0, 4) and (2, 0)
2006-07-19 16:04:07
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answer #4
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answered by jimbob 6
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Well, if 2x+y = 4, then it resolves to y = 4 - 2x, or more succintly, y = -2x + 4, so....
At x = 0, y = 4
At x = 1, y = 2
At x = 2, y = 0
etc. etc
2006-07-19 14:37:39
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answer #5
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answered by marsroxx 2
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Anywhere that makes the equation true. Two easy ones are those for X = 0 and Y = 0: (0,4) and (2,0)
2006-07-19 13:54:37
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answer #6
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answered by Anonymous
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y= -2x +4
slope (or gradient) is -2, since the coefficient of x is -2, (which means a downward sloping curve).
y-intersection is at +4
2006-07-19 13:55:47
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answer #7
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answered by ginandvodka 3
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y=-2x+4 so
0, 4
1, 2
2,0
and so on...
2006-07-19 13:54:48
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answer #8
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answered by Ben D 2
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