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Imagine a plane is sitting on the beginning of a massive conveyor belt/travelator type arrangement, as wide and as long as a runway, and intends to take off. The conveyer belt is designed to exactly match the speed of the wheels at any given time, moving in the opposite direction of rotation.
There is no wind.
Can the plane take off?

This is a question that will make you think. There is a correct answer and if you really want to know it then e-mail me.

2006-07-19 12:40:08 · 11 answers · asked by Shortstuff71 3 in Science & Mathematics Physics

11 answers

Sure can.
Speed of the wheels has nothing to do with velocity.
The plane will move forward because the engine is pulling itself through the air.
As the speed of the plane increases so do the wheels and the belt. The speed of the wheels will be faster than normal but it will move forward.
Forward motion is not created from the wheels as is a car.
Motion is created with thrust from the engines.
If he hit the brakes, well that is another matter.

2006-07-19 13:37:49 · answer #1 · answered by beedaduck 3 · 1 2

Small piston engine airplanes use max throttle for all takeoffs. For causes too distinctive to point the following, jet airplane under no circumstances use finished throttle except there is FADEC accessible. Even then, the pcs received't enable the engine bypass to finish skill. In our older 727, we'd want to calculate the EPR putting on the engines previous to each takeoff. that is many times depending on the temperature. The pilot flying will set that EPR putting initially and then at about 100 knots or so the engineer will attain up and push the throttles ahead somewhat to reset the EPR to the unique putting. It drops off somewhat as you income airspeed you be conscious. besides the actuality that if an engine fails it isn't any longer a tremendous theory generally to bypass to finish skill on the last engines. the undertaking then is in case you could put in extra asymmetrical thrust than the rudder can manage on the computed 2d section climb p.c.. each little thing has already been planned for the shortcoming of an engine so that you only fly with what you've were given till you get to a secure altitude and then freshen up the airplane and commence determining what to do next.

2016-10-14 23:35:06 · answer #2 · answered by ? 4 · 0 0

No. The plane wouldn't be moving, and no lift would be able to accumulate underneath the wings. To the first answerer, It would NOT travel faster, just a greater distance with no speed. You also have to keep in mind, I know this is a "pandora's box" kind of thing, but that as the engines work faster and faster, the conveyer belt would have to speed up. Eventually the plane may move if the conveyer belt didn't go faster, but it wouldn't be sufficient to liftoff.

2006-07-19 13:02:02 · answer #3 · answered by Anonymous · 0 0

It is virtually impossible for the plane to take off, here's why.

The planes engine would have to create a large enough acceleration to get to flight speed before the conveyer belt could readjust its speed to match the new tire speed.

This means that the plane has a fraction of a second to get up to speed.

It’s like a runner on a treadmill. He only moves forward on the mill if he runs faster than the belt under his feet.

2006-07-19 12:48:23 · answer #4 · answered by Anonymous · 0 0

I don't think it can, because what makes it possible for the plane to take off is the lift provided by air rushing under and over the wings (Bernoulli's Principal). The air under the wings is denser than the air over the wings, and the pressure difference provides the lifting force. Since the belt matches the plane's speed exactly in the opposite direction, it never moves from the same spot. Therefore there is no air moving under or over the wings - and no lifting force.

2006-07-19 12:49:13 · answer #5 · answered by Zelda Hunter 7 · 0 0

NO, the plane needs to have velocity to generate enough lift on the wings. If the conveyor was canceling out the velocity of the craft, it is going nowhere. Why would just the wheels moving make the plane take off?

2006-07-19 12:49:39 · answer #6 · answered by Christopher 4 · 0 0

No. If the plane isn't moving there is no lift being created underneath the wings. You conveyor is counteracting the speed and forward rotation of the wheels on the plane, so the plane would essentially be stationary.

2006-07-19 12:45:15 · answer #7 · answered by J.D. 6 · 0 0

A prop plane maybe, if somehow the wind developed by the props was enough for the lift to overcome the planes weight... not a likely design for a plane. Obviosly, a harrier could do it or any other similar jet with more vertical thrust then the thing weighs.

2006-07-19 13:10:33 · answer #8 · answered by Anonymous · 0 0

No, it will not fly because an airfoil (the wing of the plane) needs are over the wind to obtain lift. Lift is necessary to pick the airplane off the runway.

2006-07-19 12:47:05 · answer #9 · answered by Skypilot49 5 · 0 0

Duh, it'd go faster.
---> planes wheels
<--- conveyor belt

2006-07-19 12:44:06 · answer #10 · answered by a_digitaldreamer 2 · 0 0

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