2006-07-19 10:31:17 · 4 answers · asked by joeduncuff 1 in Science & Mathematics ➔ Chemistry
Depends on the pH.
Most chlorine bleach is stabilised to the alkaline side, so it (mostly) exists as the hypochlorite anion. (OCl-)
As you shift the system to the acid side you first form free hypochlorous acid (between approx pH 4 - pH5.5 all of the hypochlorite exists as hypochlorous acid HOCl), and below pH4 it starts to release free chlorine.
If you send it very acid, it releases all of the product as chlorine gas.
So, in 1 litre of a 10.5% (w/v) Sodium hypochlorite solution, you have 105g of Sodium Hypochlorite (NaOCl - m.w. 74.44) which is 47.62% by weight Cl ( or 50g). So you have 5% available chlorine (w/v) in a 10.5% Sodium hypochlorite solution.
2006-07-19 20:06:31 · answer #1 · answered by Bruce H 3 · 0⤊ 0⤋
There might be none. Sodium hypochlorite is NAOCl2. I think the CL always stays bonded to the oxygen, so maybe the answer is none. The NA+ separates and the OCl2- comes off of that.
2006-07-19 11:54:58 · answer #2 · answered by JoeIQ 4 · 0⤊ 0⤋
http://www.powellfab.com/technical_information/preview/general_info_about_sodium_hypo.asp
Several things to note. if there are other species in the water, the chlorine may be present as combined chlorine, not free.
Also, 10.5% is an approximation and changes on air exposure and with time.
2006-07-19 17:47:14 · answer #3 · answered by Peter Boiter Woods 7 · 0⤊ 0⤋
Sounds too much like a homework question, instead ask for leads not the answer
2006-07-19 10:50:04 · answer #4 · answered by Peach 4 · 0⤊ 1⤋