Yuri has a board that is 98 in. long. He wishes to cut the board into two pieces so that one piece will be 10 in. longer than the other. What should the length of each piece be?
This needs to be an algebric equation, please help. Thank you in advance!!!
2006-07-19 10:23:41 · 7 answers · asked by sistermoon 4 in Education & Reference ➔ Homework Help
That was very helpful, now I understand it, thank you everyone. It is so great that you take the time to help others like this.
2006-07-19 11:17:14 · update #1
The short piece is (x) long, the long piece is (x+10) long and their lengths have to add up to 98, so write it out:
x+(x+10) = 98 ...now take of parenthesis and combine terms
2x+10 = 98 ...now subtract 10 from both sides
2x = 88 ...now divide both sides by 2
x = 44 ...this is the length of the short board, so the other board is 44+10 = 54, now we can check to see if the lengths add to 98:
44+54 = 98.
So we found the right answer.
2006-07-19 10:28:33 · answer #1 · answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6 · 0⤊ 0⤋
Okay.
Let x = the lengh of the first piece
Let y = the length of the second piece
One needs to be 10 inches longer than the other, so you could say the first piece, plus 10 inches, equals the second piece.
x + 10 = y
You know that the two pieces equal the total length of the full board, which is 98 inches.
x + y = 98
Now you have two equations:
y = x + 10
x + y = 98
Since you have a value for y (x + 10), you can plug it into the second equation like this:
x + (x + 10) = 98
x + x + 10 = 98
2x + 10 = 98
2x = 88
x = 44
Now that you know the value of x, plug it into the first equation to find y.
y = x + 10
y = 44 + 10
y = 54
One piece is 54 inches long. The other piece is 44 inches long.
If you need any more help, feel free to contact me.
2006-07-19 10:33:22 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Its E-Z. Look, first identify your variables. lst piece is represented by this equation; X+10. The second piece is represented by; X. now what yu do is you add these to equations together like this and equal them to 98in.
x+10+X=98
2X+10=98
-10=-10
2X=88
then divide 88 by 2 to isolate your variable and you get 44, which is the answer for the second piece because what you did is you isolated your X variable which as we said eariler represented your second piece of the board. now to find the first piece just add 44 to 10 and you get 54 for the first piece of wood. Why do you do this? because you are just plugging in the value of x into your first equation: X+10. so your answers are 54 for the first piece and 44 for the second piece. you know this is correct because one of the pieces is exactly 10in longer then the other. Do you get it now?
2006-07-19 10:39:02 · answer #3 · answered by funkucla!!! 3 · 0⤊ 0⤋
The algebriac equation is x+(x+10)=98.
The short piece is x.
The long piece is (x+10)
Then you combine like terms to make it 2x+10=98.
Then you subtract ten from both sides. -10 -10
Then you divide by two on both sides. 2x/2=88/2.
Then you get x=44.
So the first board is 44 inches long and the second board is 54
inches long.
Feel free to ask any questions
2006-07-19 10:30:40 · answer #4 · answered by Anonymous · 0⤊ 0⤋
(98-10)/2=44 than add 10 to one of the 44
Answer 54 in. long and, 44 in. long
That was easy
2006-07-19 10:30:54 · answer #5 · answered by Anonymous · 0⤊ 0⤋
44 and 54
2006-07-19 23:03:06 · answer #6 · answered by phoenix 1 · 0⤊ 0⤋
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2016-12-10 10:25:30 · answer #7 · answered by hillis 4 · 0⤊ 0⤋