2006-07-19 09:27:14 · 4 answers · asked by the_wicked_itch_of_the_west 3 in Education & Reference ➔ Homework Help
-.3010299957
2006-07-19 09:30:54 · answer #1 · answered by a_digitaldreamer 2 · 0⤊ 0⤋
Assuming you mean "log base 8 of 1/16"...
It's asking for the value of x in the equation
8^x = 1/16
Both 8 and 1/16 can be written as powers of 2: 8=2^3 and 1/16=2^-4. So we have
(2^3)^x = 2^-4
or
2^(3x) = 2^-4
Then log-base-2 both sides, and you have
3x = -4
or
x = -4/3 = ~ -1.333
2006-07-19 16:46:00 · answer #2 · answered by Matt E 2 · 0⤊ 0⤋
Okay.
log_8(1/16) = x
Change to exponential.
8^x = 1/16
Write the 8 and 1/16 in terms of 2.
8 = 2^3
1/16 = 2^-4 (the negative 4 takes the number out of the denominator)
Now, you have:
2^3x = 2^-4
Since both sides are equal, with the same base, you have to assume the exponents are equal.
3x = -4
x = -4/3
So, log_8(1/16) = -4/3
2006-07-19 17:06:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋
-.3010299957
if u have alot of problems like these you can use a graphing calculator, like the TI-83 or TI-84
2006-07-19 16:33:32 · answer #4 · answered by ily ♥ 3 · 0⤊ 0⤋