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24 answers

The sum of an arithmatic series:
S= (n/2)*{ a+ L}, where n is the number of terms, a is the first term and L is the final term.
so S= (500/2)*{ 1+500} = 250*501 = 125250

2006-07-19 08:35:49 · answer #1 · answered by Anonymous · 2 1

The sum of the first n integers (1+2+3+4+5+...+n) is n*(n+1)/2 (in other words, n times (n+1) divided by 2).

Let's use your question as an example. 1+500=501. 2+499=501. 3+498=501. Keep going up 1 in the first term and down 1 in the second (so the next would be 4+497=501) all the way up to 250+251=501. You have now grouped the numbers into 250 sets of 501. Add them and get 250*501, which is 500*501/2. (The answer is 125,250.)

2006-07-19 09:32:24 · answer #2 · answered by galactonerd 2 · 0 0

The formula to find out the sum of first n natural numbers is {n(n+1)} / 2

For example sum of first 10 natural numbers is 10(11)/2 = 55
In the similar way you can find it for 100 it is as follows
100(101)/2 = 5050.

For the first 500 numbers it is 500(501)/2 = 125250
Therefore 1+2+3+...+500 = 125250

Similarly you can do it for any numbers.

Hope you understood it.

2006-07-19 06:30:54 · answer #3 · answered by Sherlock Holmes 6 · 0 0

I don't know the answer right offhand, but I recommend to you a great children's book, called One Grain of Rice, by Demi.

It is considered to be a mathematical folktale that basically follows the pattern of adding 1+2+3+4+ all the way up to 30.

It shows the Math problem in the back of the book. It's amazing how high the number gets, just going to 30....up in the millions, I think...or billions...

2006-07-19 06:27:36 · answer #4 · answered by scruffycat 7 · 0 0

= N(First + Last)/2
Which would be 500(500+1)/2=125250

2006-07-19 06:25:44 · answer #5 · answered by Anonymous · 0 0

501 X 500 then divide by 2
250500 / 2 = 125250

for any amount of consecutive numbers n,
(N X (N+1)) /2

2006-07-19 09:14:12 · answer #6 · answered by beee_very_careful 1 · 0 0

s= n/2{2a+(n-1)d}
= 500/2 { 2*1+(500-1)*1}
= 250 {2+499}
=250*501
= 125250

2006-07-19 08:35:55 · answer #7 · answered by flori 4 · 0 0

(1 + N)*(N/2)

2006-07-19 06:26:09 · answer #8 · answered by Anonymous · 0 0

it is simply 500 times 501 divided by 2

write the numbers once as increasing, then another row as decreasing:

1 2 3... 500
500 499 488 ... 1
________________
501 501 501 ... 501

that is exactly 500 times 501... one sum therefore would be to divide it by 2!

:-) sweet question.

2006-07-19 07:51:13 · answer #9 · answered by Hibernating Ladybird 4 · 0 0

1 + 500 = 501; 2 + 499 = 501; etc.

There are 250 such pairs.

250 * 501 = 125,250

Or you can add them all up.

2006-07-19 06:24:26 · answer #10 · answered by Steve W 3 · 0 0

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