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a. True

b. False


AND:


The solution to the inequality x – 6y > 12 is graphed using a dashed boundary line.

a. True

b. False

2006-07-19 05:57:40 · 5 answers · asked by Brandon ツ 3 in Science & Mathematics Mathematics

5 answers

Okay, the first one. Just plug in the point.

(6,4) = (x,y)

y < x - 1
4 < 6 - 1
4 < 5

A. True

Next.

Yes. When you have a greater than sign, or a less than sign, you use a dashed boundary line. When you have a greater than or equal to sign or a less than or equal to sign, you use a solid line.

A. True.

2006-07-19 06:53:47 · answer #1 · answered by Anonymous · 3 0

In my previous answer I told you how to do these type of answers.

I am also giving it once again. Just substitute the given point in the inequation and verify whether it is correct or not. If it is correct, then the point satisfies the inequation otherwise not.

Substituting the point, gives 4 < 6-1 which is true. So the point satisfies the given inequation.

Comming to the second part.
It is true that the solution to the inequality x – 6y > 12 is graphed using a dashed boundary line as in the given inequation there is no equal to sign so the region does not include the area on the line. So the solution to the inequality x – 6y > 12 is graphed using a dashed boundary line only.

Hope you can understand this easily.

2006-07-19 06:47:25 · answer #2 · answered by Sherlock Holmes 6 · 0 0

True. Using 6 and 4 as points on a graph, use 6 as your X axis and 4 as your Y axis. Then, putting those into the equation 4<6-1. True.

The second part, what is X and what is Y? Yes, true. use a dashed (or dotted) line to symbolize a greater than or less than.

2006-07-19 06:03:04 · answer #3 · answered by Scott D 5 · 0 0

The answer to the first question is true. 6-1 is greater than 4

I would use a dashed boundary line because it is not equal to, so points on the line are not answers. True as well

2006-07-19 06:00:39 · answer #4 · answered by Anonymous · 0 0

I suck at math, sorry good luck!

2006-07-19 06:02:15 · answer #5 · answered by Anonymous · 0 0

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