Absolute value means that whatever number is within the bars, you make it positive. Therefore you want x-1 to equal 3 or -3 because once you take the absolute value, you will have 3 either way.
If x-1 = 3 or x-1 = -3, then x= -2 or 4
Solve the next equation the same way:
so that 2x+3 gives you 2 and -2.
2x+3 <= 2 and 2x+3 <= -2
Solving these you find that x<= -1/2 or x<= -5/2, which gives you the range -5/2<=x <= -1/2
2006-07-19 05:43:07
·
answer #1
·
answered by KT 2
·
1⤊
0⤋
First solving the first one.
Ix-1I = 3
gives x-1 = 3, -3
First taking 3 and solving.
x-1 = 3 implies x = 4
Now taking -3,
x-1 = -3 implies x = -2.
Therefore the solution for the first question is x = -2 and 4.
Now commimg to the second one.
The given inequality can be written as
-2 <= 2x+3 <= 2 , According to the definition of modulus.
subtracting 3 in the above equation, gives
-5 <= 2x <= -1
Now dividing with 2, gives
-5/2 <= x <= -1/2.
Therefore x belongs to the interval, (-5/2,-1/2)
This can also be written as (-2.5,-0.5)
Hope you can understand the above explaination.
2006-07-19 07:40:06
·
answer #2
·
answered by Sherlock Holmes 6
·
0⤊
0⤋
Okay. When you find the absolute value of a number, it is always positive. For example:
| 1 | = 1, | -1 | = 1
This being said, you need to split this into two equations. You have to take into account, what if the equation inside the absolute value is negative.
| x - 1 | = 3
x - 1 = 3
x = 4
-(x - 1) = 3
-x + 1 = 3
-x = 2
x = -2
The answers are 4, -2.
Next. Same thing.
| 2x + 3 | <= 2
2x + 3 <= 2
2x <= -1
x <= -1/2
-(2x + 3) <= 2
-2x - 3 <= 2
-2x <= 5
x <= -5/2
Your answer is:
x <= -1/2, x <= -5/2
If you need any more help, feel free to click the avatar next to my name, then click contact me. You can email me your questions. I would be glad to help.
2006-07-19 07:05:15
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
A)
|x - 1| = 3
x - 1 = +3 or x - 1 = -3
x = 4 or x = -2
B)
|2x + 3| <= 2
2x + 3 <= +2 or 2x + 3 >= -2
x <= (-1/2) or x >= (-5/2)
which means x is between -1/2 and -5/2, (-5/2 <= x <= -1/2)
2006-07-19 17:13:16
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
|x - 1| = 3 , x - 1 = 3 or x - 1 = -3 , x = 4 or x = -2
|2x + 3| <= 2 , -2 <= 2x + 3 <= 2 , -5 <= 2x <= -1 ,
-5/2 <= x <= -1/2
2006-07-19 05:41:00
·
answer #5
·
answered by Dimos F 4
·
0⤊
0⤋
Just set x-1 = 3, then x-1 = -3. You get 4 and -2.
For the inequality, split it into
-2 <= 2x+3 <= 2.
Sub. 3 from each end: -5<= 2x <= -1.
Div. thru by 2: -2.5 <= x <= -.5
2006-07-19 05:32:49
·
answer #6
·
answered by jenh42002 7
·
0⤊
0⤋
The symbol on the keyboard is Shift-\. You should find the \ above the Enter/return key or below it, depending on the version and age of your keyboard. If your keyboard is for Mac, I don't think there is a \ key there...
x = 4 for problem 1.
x≤-0.5 and x≥-2.5 for problem 2.
2006-07-19 05:38:34
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
|x-1|=3
x-1=3 or x-1=-3
x=3+1 or x=-3+1
x=4 or x=-2
|2x+3|<=2
-2<=2x+3<=2
-2-3<=2x<=2-3
-5<=2x<=-1
-5/2<=x<=-1/2
-2.5<=x<=-0.5 or in fractions, -2 and1/2 <=x<=-1/2
2006-07-19 05:35:09
·
answer #8
·
answered by Cara B 4
·
0⤊
0⤋
Ix-1I=3 then
Ix=3+1I then
x=(3+I)/l
2006-07-19 05:35:01
·
answer #9
·
answered by Preykill 5
·
0⤊
0⤋
| x |=4
|2x+3| < 2
-3
| 2x | <-1
/2
| x | < -1\2
2006-07-19 05:34:01
·
answer #10
·
answered by Jordin 3
·
0⤊
0⤋