If 15 of the Fortune 500 companies have their headquarters in Michigan and 6 have their headquarters in Maryland, what is the probability that 2 firms selected at random from the list of 500 would have one Michigan and one Maryland firm?
2006-07-19 05:14:40 · 5 answers · asked by Olu 1 in Science & Mathematics ➔ Mathematics
probability to get a michigan company - 15/500
probability to get a maryland company - 6/500
Choose a michigan company - 15/500, pick a maryland company from the remaining companies - 6/499
multiply the two choices = 90 / 249500
now, you could also choose the maryland company first, so multiply those odds by 2 (two different ways of doing it)
final odds: 180/249500 = 0.0007214
Hope that helps :-)
2006-07-19 05:23:27 · answer #1 · answered by bablunt 3 · 7⤊ 1⤋
So the total number of combinations of picking 2 firms is (500 choose 2) = 500*499/2
the number of combinations of picking your specific pairs is 15*6
the prob then is (15*6)/(500*499/2)
2006-07-19 05:24:50 · answer #2 · answered by cw 3 · 0⤊ 0⤋
15/500 * 6/499, which amounts to about 0.000360721.
But then there are half the possibilities, because of combinations, so it amounts to 0.000721442, or 180/249500. those people are right.
2006-07-19 05:25:49 · answer #3 · answered by Anonymous · 0⤊ 0⤋
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2016-12-01 22:11:09 · answer #4 · answered by Anonymous · 0⤊ 0⤋
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2006-07-19 05:17:52 · answer #5 · answered by Amanda 2 · 0⤊ 0⤋