Urgent Graphing Problem?

Question

Problem 1.

Choose the graph of the system of inequalities:
y > –3
x < 2


Problem 2.

Choose the graph of the system of inequalities:
y > 2 – x
y < –2 – x

I looking for a miracle because I do not think it is possible to show a graph on Yahoo Answers(-:

Answer 1

The first one should show a dotted horizontal line at y = - 3 and a dotted vertical line at x = 2. The shaded region is the region above the horizontal line and to the left of the vertical line.

The second one should show a dotted line running at a downward from left to right at a 45 degree angle and going through the number 2 on the y axis and a second dotted line parallel to the first going through the number -2 on the y axis. The shaded region should be the region outside the two parallel lines. (Really, the way you've described it, there shouldn't be a graph of this one at all because the two inequalities have no points in common. If you got the signs reversed, the shaded area should be between the two lines. If you are asked to graph the region satisified by one inequality OR the other, then the shaded region is on the outside.)

Answer 2

draw a dotted horizontal line in the point y= -3 and a dotted vertical line where x=2. Shade the right side of the vertical line, and the lower side of the horizontal one. The unshaded region is the required region.

for the second problem, take any two values of y, and solve each equation. For example, take y=0 and y = 2. for the first equation, which is y= 2 -x, when y=0 , x= 2, when y=2, x=0
so draw a line that passes through the points (2,0), (0,2) for the first eqution.
for the second equation, taking y=0, then x= -2, and when y=2, then x= -4. so draw a second line for the second equation, which passes through the points (-2,0) and ( -4,2).
after that take any point on the graph, and extract its coordinates. for example, take the point (0,0) and solve for both equations.
for the first 0>2 is wrong, and for the second 0<-2 is also wrong, so you shade the area between the two lines to eliminate it.
do this for any other points to figure out the region required.
I think that there is no solution for the second problem, since each inequality eliminates the results of the other one.

Answer 3

Problem 1 results in a whole shading area starting from (2, -3) and going northwest. But, this area does not include y=-3 and x=2.

Problem 2 results in a shading strip that passes through the line (y = -x) from (-1, 1) to (1, -1) and going perpendicularly in both directions. This strip does not include y = 2-x and y = -2-x.

EDIT: Okay, so I was wrong about problem 2. The whole graph is shaded except for a strip that passes through the line (y = x) from (1,1) to (-1,-1) and going perpendicularly in both directions. The non-shaded strip includes y = 2-x and y = -2-x.

Answer 4

I took 2 years of calculus in severe college (AB and BC) and AP ideas, and that i really used a TI-eighty 3 plus, and to be fairly honest it is all you want, highly if you're good at math and do not choose your calculator to do each and each little aspect for you. That having been reported, with the recommendations you've given, bypass with the TI-eighty 4 so as so that you would possibly want to prepare it to any attempt that you're taking, no adventure determining to purchase an 89 then wanting yet another calculator for SAT/ACT/competitions.

Answer 5

for a graph, go to www.quickmath.com, click Plot under Inequalities, then click Advanced, the type in your problem and it will graph it for you.

Answer 6

for first
i can not draw in this place but it is a rectangle whit this head (2,-3),(-∞,-3), (-∞,+∞),(2,+∞)
and second
2-x 2 2<-2 )
it can not be righ!!!!