a jet accelerates from rest to liftoff speed of 73.7 m/s in 27.1 s. Each of the plane's two jet engines provides a forward force of 111 kN. a) What is the mass of the plane and b) how far does it travel down the runway before liftoff?
2006-07-19 04:50:16 · 7 answers · asked by Lou 1 in Science & Mathematics ➔ Physics
Not gonna do it for you but...
You know there are 2 engines putting out 111 kN thrust... so total thrust is 222 kN. You know the initial and final speed and how fast it reached the final speed. From that you can find acceleration by the equation v = a*t...
F = m*a... you know force and acceleration by this point, solve for mass...
as for distance... the equation is
x = V(o)t+.5*a*t^2... where V(o) is 0 for initial velocity
2006-07-19 04:56:23 · answer #1 · answered by AresIV 4 · 1⤊ 0⤋
Acceleration = Change in velocity/change in time = 73.7/27.1 = 2.7196 m/s^2
Mass = Force/Acceleration = 111000*2/2.7196 = 81631 kg
The second part you can get by knowing the acceleration and using simple calculus.
2006-07-19 11:57:18 · answer #2 · answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6 · 0⤊ 0⤋
You need to add lift coefficients as well as wind vectors and velocity for a mass answer and liftoff point.
2006-07-19 11:55:13 · answer #3 · answered by Ron K 3 · 0⤊ 0⤋
F = m*a, you know change in speed and change in distance you can find avg acceleration, and solve for mass
with this avg acceleration and starting at rest, s = 0.5*a*t^2
2006-07-19 11:57:07 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Without know wing span or any other deatils of the craft it is not possible to tell you.
2006-07-19 11:54:25 · answer #5 · answered by Anonymous · 0⤊ 0⤋
a) Look at the gwvr sticker. b) when the pilot pulls the stick back.
2006-07-19 11:54:43 · answer #6 · answered by Ricky J. 6 · 0⤊ 0⤋
456879 trillion s to be exact.
2006-07-19 11:53:56 · answer #7 · answered by minus 7 · 0⤊ 0⤋