Multiple choice Evaluate (calculus)?

Question

Evaluate (from -3 to -1) (x^2 + x + 8) dx

Please show your work step by step

(a) 109 / 3

(b) 127 / 6

(c) 62 / 3

(d) 41 / 2

Answer 1

Answer is (C) 62/3

Integrating (x^2 + x+8)dx=
(x^3)/3 + (x^2)/2+8x is subject to limits (-3 to -1)

substituting the upper limit first (-1) and then subtracting the lower limit (-3) we have;

(-1/3 +1/2-8)-(-27/3 +9/2 -24)=
26/3 -8/2 + 16=62/3

Answer 2

Step one: integrate.

The integral of (x^2 + x + 8)dx is (1/3)x^3 + (1/2)x^2 + 8x

Step two: substitute for limits.

1/3(-3)^3 + (1/2)(-3)^2 + 8(-3) = -9 + 4.5 - 24 = -28.5
1/3(-1)^3 + (1/2)(-1)^2 + 8(-1) = -1/3 + 1/2 - 8 = -7 5/6

Step three: subtract.

(-28 1/2) - (-7 5/6 = 20 2/3, or 62/3

Your answer is c.

Answer 3

x^2 + x + 8 dx = (x^3)/3 + (x^2)/2 + 8x
(-3) -27/3 + 9/2 + (-24) =
(-1) -1/3 + 1/2 + (-8) =

-54/6 + 27/6 - 144/6 = -171 / 6
-2/6 + 3/6 - 48/6 = -47 / 6

= 124 / 6 ... = 62 / 3 "C"

Answer 4

x^3/3+x^2/2+8x from -3 to -1
so (-1/3+1/2-8)-(-27/3+9/2-24)
1/6-8+9-9/2+24
(1-48+54-27+144)/6
124/6

So c is the answer

Answer 5

Integral (x^2 + x + 8) dx from -3 ---> -1

=(1/3)x^3 + (1/2)x^2 + 8x from -3 ---> -1

=[(1/3)(-1)^3 + (1/2)(-1)^2 + 8(-1)] - [(1/3)(-3)^3 + (1/2)(-3)^2 + 8(-3)]
= (-1/3) + (1/2) - 8 + 9 - (9/2) + 24 = (-1/3) + 21 = 62/3

C

Answer 6

(X^3)/3+(X^2)/2+8X

((-3^3)/3+(-3^2)/2+8*-3) - ((-1^3)/3+(-1^2)/2+8*-1) = -27/3+9/2-24) - (-1/3+1/2-8)

(-9+4.5-24) - (-2/6+3/6-8) = -28.5 - (-1/6-8)

-20.5+1/6 = -101/5 + 1/6

5/30 - 606/30 = -601/30

have you done your maths?

Answer 7

The derivative of x^2+x+8 is 2x+1. All I see are rational answers, which do not correspond to the original question. Ya might want to check YOUR math, friend. :-)

Answer 8

integration of (x^2 + x + 8) dx

= (x^3)/3 + (x^2)/2 + 8x + C (constant)

I have solved the sum but couldn't understand what you meant by "(from -3 to -1)"

hope you can solve it from here....

cheers!!!

Answer 9

Infinity. the cubic root of x because it strategies infinity is infinity. so as that and considering the fact that the x being more suitable to e is likewise drawing near infinity, the final function does mind-set infinity. Klg.

Answer 10

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