Answer is (C) 62/3
Integrating (x^2 + x+8)dx=
(x^3)/3 + (x^2)/2+8x is subject to limits (-3 to -1)
substituting the upper limit first (-1) and then subtracting the lower limit (-3) we have;
(-1/3 +1/2-8)-(-27/3 +9/2 -24)=
26/3 -8/2 + 16=62/3
2006-07-19 03:46:05
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answer #1
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answered by Edward 7
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Step one: integrate.
The integral of (x^2 + x + 8)dx is (1/3)x^3 + (1/2)x^2 + 8x
Step two: substitute for limits.
1/3(-3)^3 + (1/2)(-3)^2 + 8(-3) = -9 + 4.5 - 24 = -28.5
1/3(-1)^3 + (1/2)(-1)^2 + 8(-1) = -1/3 + 1/2 - 8 = -7 5/6
Step three: subtract.
(-28 1/2) - (-7 5/6 = 20 2/3, or 62/3
Your answer is c.
2006-07-19 03:52:52
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answer #2
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answered by jimbob 6
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x^2 + x + 8 dx = (x^3)/3 + (x^2)/2 + 8x
(-3) -27/3 + 9/2 + (-24) =
(-1) -1/3 + 1/2 + (-8) =
-54/6 + 27/6 - 144/6 = -171 / 6
-2/6 + 3/6 - 48/6 = -47 / 6
= 124 / 6 ... = 62 / 3 "C"
2006-07-19 03:54:10
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answer #3
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answered by Brian D 5
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x^3/3+x^2/2+8x from -3 to -1
so (-1/3+1/2-8)-(-27/3+9/2-24)
1/6-8+9-9/2+24
(1-48+54-27+144)/6
124/6
So c is the answer
2006-07-19 03:50:47
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answer #4
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answered by Roxi 4
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Integral (x^2 + x + 8) dx from -3 ---> -1
=(1/3)x^3 + (1/2)x^2 + 8x from -3 ---> -1
=[(1/3)(-1)^3 + (1/2)(-1)^2 + 8(-1)] - [(1/3)(-3)^3 + (1/2)(-3)^2 + 8(-3)]
= (-1/3) + (1/2) - 8 + 9 - (9/2) + 24 = (-1/3) + 21 = 62/3
C
2006-07-19 17:34:58
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answer #5
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answered by Anonymous
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(X^3)/3+(X^2)/2+8X
((-3^3)/3+(-3^2)/2+8*-3) - ((-1^3)/3+(-1^2)/2+8*-1) = -27/3+9/2-24) - (-1/3+1/2-8)
(-9+4.5-24) - (-2/6+3/6-8) = -28.5 - (-1/6-8)
-20.5+1/6 = -101/5 + 1/6
5/30 - 606/30 = -601/30
have you done your maths?
2006-07-19 04:12:55
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answer #6
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answered by kohf1driver 2
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The derivative of x^2+x+8 is 2x+1. All I see are rational answers, which do not correspond to the original question. Ya might want to check YOUR math, friend. :-)
2006-07-19 03:37:33
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answer #7
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answered by Lonnie P 7
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integration of (x^2 + x + 8) dx
= (x^3)/3 + (x^2)/2 + 8x + C (constant)
I have solved the sum but couldn't understand what you meant by "(from -3 to -1)"
hope you can solve it from here....
cheers!!!
2006-07-19 03:58:37
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answer #8
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answered by abns_uk 2
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Infinity. the cubic root of x because it strategies infinity is infinity. so as that and considering the fact that the x being more suitable to e is likewise drawing near infinity, the final function does mind-set infinity. Klg.
2016-11-06 20:05:15
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answer #9
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answered by Anonymous
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zxasd
2014-07-24 06:29:49
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answer #10
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answered by Anonymous
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