How is the speed of light constant 'c' related to energy and mass in the equation 'E=mc²'?

Answer 1

The value of "c" is not that of numerical value only. Although it relates to the speed of light, it also has an energy value. There is a physics trilogy that explains this:

E = mc2, is that for mass being divided by time (time in this instance is described by "c", but itself must have a particular value in order to relate to another value. If this were not true, then the value of "c" would be zero.

m = E/c2, describes energy as being divisible by a value other than zero.

c2 = E/m, is the equation for a field of physical time, or of a gravitational field. It is a particular value, whose existence is found by dividing energy (in this case heat energy within a mass) by the mass.

The value of energy "E" may be determined by the following:

hf = E, This is energy in waveform

hf = mk, is kinetic energy found in a moving mass. The value of the above is also the same in hf = mk due to mass being composed of electromagnetic energy.

hf = c, is that of gravitational waves. Notice that these waves have a particular value (possibly that of "h") and are not zero.

Answer 2

After Einstein's theory was known, and after Fermi had done his chain reaction experiment on the racquetball court, a mother and son [I apologise, but I forget their names] team of scientists were performing their own experiments with fission. They were the first scientists to observe and measure an interesting thing. When an atom is split by fission, the mass of the resulting parts does not total the mass of the initial whole atom. Some of the matter was gone, but their experiment yielded [I think it was] 200 million eV of energy. When they did some calculations and further runs of their experiment, they realised that the missing matter had been converted to energy. At what rate was this matter converted? The ratio of energy, or E, yielded from a certain amount of matter, or m, is the speed of light, or c, squared. Einstein's most famous equation consistently let the team know how much energy was going to come out from each run of their experiments.
This also applies to a fusion process. The resulting matter after two atoms have been fused does not quite add up to the total matter of the two initial atoms.

Answer 3

In classical physics mass and kinetic energy was related by the equation, E = 1/2 mv^2.

In special theory of relativity, mass, length and time, the fundamental quantities are not constant with speed. They vary according to the speed.

Mass increases with speed,length decreases with speed and time goes slow with speed.

When an object approaches the speed light, mass tends to infinity; length and time tends to zero.

Thus there is a maximum limit for the velocity of any material object which is found to be the speed of light.

Naturally the kinetic energy of motion also depends upon the speed of light.

Using mathematics it was shown that the kinetic energy of any body is not equal to 1/2 m v^2 but it is m c^2.

The m here is the increase of mass with speed and not the mass of classical physics which was considered to be a constant.

Thus the speed of light comes into the equation to find the kinetic energy of motion of a material body.

Answer 4

The speed of light squared times mass equals energy.

Answer 5

E is equal to m c-squared, in which energy is put equal to mass, multiplied by the square of the velocity of light, very small amounts of mass may be converted into a very large amount of energy and vice versa. The mass and energy are in fact equivalent, according to the formula mentioned above.

This was demonstrated by Cockcroft and Walton in 1932, experimentally."

Answer 6

E = mc2 is one of the most famous equations in physics, even to non-physicists. It states a relationship between energy (E), in whatever form, and mass (m). In this formula, c², the square of the speed of light in a vacuum, is the conversion factor required to formally convert from units of mass to units of energy, i.e. the energy per unit mass. In unit specific terms, E (joules) = M (kilograms) multiplied by (299792458 m/s)2.

Answer 7

Simply put, the formula is valid for object when they travel close to the speed of light. It is at those speeds that they experience loss of mass.
In other cases of motion, Newton's laws apply.
Compris?

Answer 8

c is indirectly proportional to m and directly proportional to square root of E

Answer 9

C=The square root of (E/m)

Answer 10

c²=E/m