does anybody know or have an idea of finding linear speed at 30 N and 40 S?
2006-07-19 00:46:05 · 7 answers · asked by princessgirl 2 in Science & Mathematics ➔ Mathematics
Force x time = mass x increase of the speed
30 N x 40 s = mass x {v(end) - v(begin)}
Do you know the mass and initial speed?
Fill it in yourself.
2006-07-19 03:18:00 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋
distance = speed x time
speed = distance/time
abs=30n + 40 s = 70
speed = sqrt (40^2+30^2)= 50
speed = 70/50 = 1.4
2006-07-19 08:16:49 · answer #2 · answered by lubetj 1 · 0⤊ 0⤋
10 south
2006-07-19 09:18:12 · answer #3 · answered by BNutzz 2 · 0⤊ 0⤋
30N + 40S
(N is + , S is -)
30+-40=-10 or 10 S
---10(units)/t where t is time since speed is distance over time----
2006-07-19 08:38:09 · answer #4 · answered by Croasis 3 · 0⤊ 0⤋
I will make N +
I will make S -
(+30) + (-40)
-10
10 S is the answer
2006-07-19 08:10:10 · answer #5 · answered by missy 4 · 0⤊ 0⤋
I think by using the resultant one can observe that the answer is 10 due South.
I considered N and S as North and South.
2006-07-19 08:05:36 · answer #6 · answered by Sherlock Holmes 6 · 0⤊ 0⤋
Just a guess... 10 S.
2006-07-19 07:51:04 · answer #7 · answered by Anonymous · 0⤊ 0⤋