please! answer! it's an assignment of mine!
2006-07-18 23:42:30 · 4 answers · asked by angel_4114 2 in Science & Mathematics ➔ Mathematics
°F = °R − 459.67
°R = °F + 459.67
2006-07-19 03:29:33 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋
The symbol is °R (note that this symbol is also used to stand for the Rømer and Réaumur scales). Like Kelvin, Rankine zero is absolute zero, but Fahrenheit degrees are used. As a result, a difference of 1 R° is equal to a difference of 1 F°, but 0 °R is â459.67 °F.
The Rankine cycle is an idealised thermodynamic cycle for a steam engine, i.e. one using water as the working fluid.
I am sure that you can get the clear idea of this if you click on the following link. http://en.wikipedia.org/wiki/Rankine
Hope this info can be correct.
2006-07-19 06:49:00 · answer #2 · answered by Sherlock Holmes 6 · 0⤊ 0⤋
Kelvin, Réaumur, and Rankine
a °C = (4/5)a °Réaumur = [32 + (9/5)a] °F
b °Réaumur = (5/4)b °C = [32 + (9/4)b] °F
c °F = (5/9)(c - 32) °C = (4/9)(c - 32) °Réaumur
t °C = (t + 273.15) K
TK K = (TK - 273.15) °C = [1.80 * (TK - 273.15) + 32] °F = 1.80 TK °Rankine
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2006-07-19 11:09:58 · answer #3 · answered by ? 3 · 0⤊ 0⤋
Can you be more clear about ur question, however
TK K = (TK - 273.15) °C = [1.80 * (TK - 273.15) + 32] °F = 1.80 TK °Rankine
Is this the answer, what you wanted??
2006-07-19 06:46:41 · answer #4 · answered by Sunil P 2 · 0⤊ 0⤋