what is log of 49 to the base 8 ???

Answer 1

log_a b=c

can be written as a^c=b;

so we can write log_8(49)=x

8^x=49

x will be approximately equal to 1.65

Answer 2

It is log base 10 of 49 divided by log base 10 of 8 which is 1.871569948.

Answer 3

It is not possible to give an exact decimal representation of this number, because it is irrational. In general, if Log[b,x] represents the base-b logarithm of x, then

b^(Log[b,x]) = x.

So in your instance, Log[8,49] is a number n that satisfies

8^n = 49.

The approximate value of n that satisfies this equation is

n = 1.8715699480 3840273829 4646211487 8872057606 8441731076 0522451527 8160468805 6590812865 7665240666 1134738567....

to 100 digits.

Answer 4

use this general equation
log b to base a = log b / log a

so log 49 base 8 = log 49 / log 8 = 1.87

Answer 5

Using the change of base formula,

log_8 (49) = ln (49)/ ln (8) ≈ 1.87

or, if you prefer base 10,

log_8 (49) = log_10 (49) / log_10 (8) ≈ 1.87

Answer 6

log49 to the base 8 = log49/log8

= log(7^2)/ log(2^3) = 2/3*( log7/log2)

= (2/3)* 2.807 = 1.872

Answer 7

=ln(49)/ ln(8)
=3.891820298/2.079441542
=1.871569948

Answer 8

1.57