How does one determine the x intercept given the y and the slope.
A line graphed has a slope of 0.6 and a y-intercept of 2. What is the x intercept?
2006-07-18 16:21:49 · 9 answers · asked by zoso_arivolk 1 in Science & Mathematics ➔ Mathematics
General line with slope 0.6 is y = 0.6*x + b
On the line is point (0 , 2), so 2 =0.6*2 + b. So b=0.8
The line is y = 0.6*x + 0.8
If y=0 then 0.6*x + 0.8 = 0. Then x=-4/3
That gives intersection point (-4/3 , 0)
2006-07-18 18:27:48 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋
Given the y intercept and the slope, form the equation of the line from them:
y = mx + b
For example, given a slope of 2/3 and a y-intercept of 4 the equation becomes
y = 2/3 x + 4.
The x intercept occurs where the y value is zero. So, after getting the equation of the line from the slope and the y-intercept, plug a value of zero in for y and solve for x. Using the guy above:
0 = 2/3 x +4
-4 = 2/3 x
-4 * 3/2 = x
-6 = x.
So, when y is zero, x is -6 and -6 is the x-intercept.
2006-07-18 16:29:04 · answer #2 · answered by tbolling2 4 · 0⤊ 0⤋
first you need to determine the equation from the information given...
when dealing with slope and intercepts.. we use the slope-intercept form of equation:
y = mx + b, where m is the slope, b is the value of the y-intercept
so.. given a slope of 0.6.. or 6/10 (which makes it easier to graph)
and a y-intercept of 2 we write the equation:
y = 0.6x + 2
now... the y-intercept is when x is zero... so it occurs at (0,2)... and the x-intercept.. is when y is zero... we can figure out the x value from this...
0 = 0.6x + 2
-2 = 0.6x
-2/0.6 = x
-1/0.3 = x
or... x = about -3.333333...
since this is a linear equation.. there is only one x-intercept
2006-07-18 17:22:34 · answer #3 · answered by ♥Tom♥ 6 · 0⤊ 0⤋
The equation of a line is
y = mx + c
Given the gradient m = 0.6
and the y-intercept = 2,
The equation of the line is,
y = 0.6 x + 2
x-intercept happens when y = 0,
0 = 0.6 x + 2
0.6 x = -2
x = -2/0.6
x = -3 1/3
2006-07-18 17:49:55 · answer #4 · answered by ideaquest 7 · 0⤊ 0⤋
put it in slope y intercept form, y=3/5x+2
to solve for the x intercept set y to 0 and you get -2= 3/5x or
-2(5/3) = x or -10/3 = x
2006-07-18 16:31:56 · answer #5 · answered by Anonymous · 0⤊ 0⤋
to find the x intercept put y=0 in the equation
slope=0.6 and passes through(0,6)
the equation is y-2=0.6(x-0)
putting y=0 in this equation,x=-3.3
so the x intercept is -3.3
2006-07-18 16:32:40 · answer #6 · answered by raj 7 · 0⤊ 0⤋
To find the x intercept, always substitute y = 0 and then solve the equation.
Your equation in this case is y = 3/5x + 2
So now just substitute in 0 = 3/5x + 2 and solve.
x = -10/3. (or -3.3)
2006-07-18 16:29:44 · answer #7 · answered by scotsgirl 2 · 0⤊ 0⤋
y = mx + b
y = (3/5)x + 2
(3/5)x = y - 2
3x = 5y - 10
x = (5/3)y - (10/3)
x-intercept = (-10/3)
2006-07-18 16:50:51 · answer #8 · answered by Sherman81 6 · 0⤊ 0⤋
y = 3/5x + 2
Set y = 0, and solve for x
0 = 3/5x + 2
-2 = 3/5x
x = -10/3
2006-07-18 16:30:08 · answer #9 · answered by Michael M 6 · 0⤊ 0⤋