math calculation
2006-07-18 13:24:25 · 6 answers · asked by Jon O 1 in Science & Mathematics ➔ Mathematics
use this general equation
nCr = n! / {r! (n-r)!}
3c2 = 3! / (2! x (3-2))! = 1 x 2 x 3 / (1 x 2 x 1) = 6 / 2 =3
2006-07-18 20:35:12 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3
2006-07-18 21:57:25 · answer #2 · answered by none2perdy 4 · 0⤊ 0⤋
If C stands for combination,
3C2 = (3*2)/[1*2] = 3
or
3C2 = 3C(3-2) = 3C1 = 3
2006-07-18 22:39:26 · answer #3 · answered by qwert 5 · 0⤊ 0⤋
3C2 = 3. It is the number of ways to choose 2 objects out of a set of three. It is easier if you realize that when you choose 2 objects, you are also NOT choosing the third object, so you could just pick the one object that you were leaving out and take the other two. There are clearly 3 ways to pick one object out of three.
2006-07-19 00:14:51 · answer #4 · answered by mathsmart 4 · 0⤊ 0⤋
if c represents combination, then the answer is 3...
3c2=3c1=3
2006-07-22 08:20:49 · answer #5 · answered by jai 2 · 0⤊ 0⤋
962
2006-07-18 20:32:09 · answer #6 · answered by Paul 2 · 0⤊ 0⤋