number ending in the same last 4 digits...e.g. not real numbers --->
123-456-1212 and 222-444-1212...
2006-07-18 13:21:28 · 5 answers · asked by Paris Hilton 6 in Science & Mathematics ➔ Mathematics
Since it doesn't matter what the first six digits are, we can ignore those. There's a 1 in 10 chance that the 7th digit will be the same (since there are 10 possible digits). There is also a 1 in 10 chance for each individual digit after that. So, we just multiply:
1/10 * 1/10 * 1/10 *1/10 = 1/10000
The chances are 1 in 10,000. That's pretty small, but to be frank, not as small as I would have guessed without doing the calculations.
2006-07-18 13:30:56 · answer #1 · answered by mathgirl 3 · 4⤊ 1⤋
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2016-12-10 09:48:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Just a rough guess, about 1 in 20,000,000
2006-07-18 13:30:21 · answer #3 · answered by Dee Dee Dee 2 · 0⤊ 0⤋
1 in 10,000
p(a|b) = p(a)
if a is independant of b
2006-07-18 15:00:42 · answer #4 · answered by none2perdy 4 · 0⤊ 0⤋
are you looking for this to be an acceptable answer?
cell: 1234
fax: 4321
?
2006-07-18 13:34:44 · answer #5 · answered by Paul 2 · 0⤊ 0⤋