2006-07-18 09:16:34 · 12 answers · asked by mbr_hm 2 in Family & Relationships ➔ Friends
No! We would both have enough sense to like different people for the reason that if one got asked out and not the other, there would be no jealousy. He's not a shirt, you cannot share him.
2006-07-18 09:21:57 · answer #1 · answered by jtj 5 · 0⤊ 0⤋
What does it mean to "share" him?
Are you going to cut him up into little pieces and divy them up?
Are you going to go on dates, all three of you?
Are you going to neck and more together?
Eventually, the sharing will stop. If you're lucky, you'll still
be friends with your best friend, but I'll bet you won't.
2006-07-18 09:21:48 · answer #2 · answered by Elana 7 · 0⤊ 0⤋
well To be honest with you, me and my best friend fought over a guy i meant literally fist fought over him, it kinda messed up our friendship up, but after years we still hardly dont talk each other, i did date him for 5 months then i moved, so were both not together with this guy, were both married to different guys. so it will kill your friendship.
2006-07-18 09:21:30 · answer #3 · answered by ~*Jenny*~ 4 · 0⤊ 0⤋
NO DONT!
Just think about if HE would like you or your best friend there solved!
2006-07-18 09:21:20 · answer #4 · answered by thatssosweetxo 1 · 0⤊ 0⤋
if i were u id tell her to back off hes ur and u shouldnt share with anyone!
2006-07-18 09:20:19 · answer #5 · answered by kayla l 1 · 0⤊ 0⤋
If that's what you and your friend agree to do, then I have no problem with it! Good luck!
2006-07-18 12:34:31 · answer #6 · answered by cryptoscripto 4 · 0⤊ 0⤋
sisters before mister all the way!
2006-07-18 10:56:49 · answer #7 · answered by Anonymous · 0⤊ 0⤋
fight for him, and who ever wins gets him. it's his choice
well if he doesn't like both of u.
2006-07-18 09:26:45 · answer #8 · answered by ♥ 4 · 0⤊ 0⤋
Once we got over the shock of being gay...... sure, why not?
2006-07-18 09:21:07 · answer #9 · answered by BrownTown 5 · 0⤊ 0⤋
uhh you cant "share" a guy.
2006-07-18 09:20:15 · answer #10 · answered by softballgirl0127 2 · 0⤊ 0⤋