Using calculator you can solve this type of problem within seconds. Apply the universal formula for this P*(1+R/100)**T
P=Principal, R=Interest Rate, T=No of times compound Interest is calculated
and for simple interest its so simple
I=pnr/100
2006-07-18 14:48:52
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answer #1
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answered by Anonymous
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Simple Interest Sums
2016-12-17 14:40:31
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answer #2
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answered by ? 4
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Compound interest = P(a million+r)^n - P [P-imperative, n-kind of yrs r-price] ordinary interest = Pnr P(a million+r)^n - P - Pnr = one hundred ten.16 right here, n=3, r = 0.06 P*[a million.06^3 - a million - 0.18] = one hundred ten.16 P * 0.011016 = one hundred ten.16 P = ten thousand to attraction to close the sum of both pastimes, it truly is: P(a million+r)^n - P + Pnr P[0.191016 + 0.18] P[0.371016] putting P as ten thousand, the sum is Rs 3710.16
2016-12-01 20:55:02
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answer #3
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answered by ? 3
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Amount* (1+r)N
Where r = rate of intrest/100
and n=number of years
if intrest is paid yearly...
2006-07-18 08:54:42
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answer #4
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answered by Ali 5
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Get a finance calculator.
2006-07-18 08:52:57
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answer #5
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answered by drumrchick 3
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