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Using calculator you can solve this type of problem within seconds. Apply the universal formula for this P*(1+R/100)**T
P=Principal, R=Interest Rate, T=No of times compound Interest is calculated

and for simple interest its so simple
I=pnr/100

2006-07-18 14:48:52 · answer #1 · answered by Anonymous · 0 0

Simple Interest Sums

2016-12-17 14:40:31 · answer #2 · answered by ? 4 · 0 0

Compound interest = P(a million+r)^n - P [P-imperative, n-kind of yrs r-price] ordinary interest = Pnr P(a million+r)^n - P - Pnr = one hundred ten.16 right here, n=3, r = 0.06 P*[a million.06^3 - a million - 0.18] = one hundred ten.16 P * 0.011016 = one hundred ten.16 P = ten thousand to attraction to close the sum of both pastimes, it truly is: P(a million+r)^n - P + Pnr P[0.191016 + 0.18] P[0.371016] putting P as ten thousand, the sum is Rs 3710.16

2016-12-01 20:55:02 · answer #3 · answered by ? 3 · 0 0

Amount* (1+r)N
Where r = rate of intrest/100
and n=number of years

if intrest is paid yearly...

2006-07-18 08:54:42 · answer #4 · answered by Ali 5 · 0 0

Get a finance calculator.

2006-07-18 08:52:57 · answer #5 · answered by drumrchick 3 · 0 0

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