Power of n?

Question

(x+d)ª, how do you times out the bracket if you don't know what a is?

Answer 1

Use the binomial theorem

(x+d)^n=(k=0, n)∑(n!/(k!(n-k)!))x^kd^(n-k)

Answer 2

LeBlanc is wrong, and so is aafarmer 2000
you cannot distribute the power if you have an addition (which you do) or a substraction. you can only distribute the power if you have a multiplication of a division
(a+b)^2 = a^2 + 2ab + b^2
(a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3
ever heard of pascal's triangle?
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
........
so what's (a+b)^4 going to be equal to?
if you caught on to the pattern, the solution is
a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4
thus, the next one down is
1 5 10 10 5 1
so (a+b)^5 = a^5 + 5a^4b + 10a^3b^2 + 10a^2b^3 + 5ab^4 + b^5

neat, huh?

Answer 3

Whatever is in the bracket is raised to the power of the exponent outside the bracket.

In your example: (x+d)^n = x^n +d^n

Consult the example section in your maths text.

Answer 4

you times it out a times, whatever a is...

if you don't know, you can't actually do it that way and will need another way to simplify

Answer 5

i think the answerwill be simply x^a +d^a

Answer 6

it would be ax+ad