Solve the systems of equation by any method:?

Question

Problem 1.

x-3y=4
-2x+6y= 3


Problem 2.

5x-y= 3
-10x+2y= 2

I love you people, thanx a million.

Answer 1

x = 3y+4
then substitute:
-2(3y+4) + 6y = 3
-6y -8 + 6y = 3
-8 = 3
this statement is false, ie. no solution

#2
y = 5x - 3
then substitute
-10x +2 (5x - 3) = 2
-10x +10x -6 = 2
-6 = 2
this statement is false, ie no solution

Answer 2

x=4+3y Equation 1

-2(4+3y)+6y=3 Equation 1 plugged into 2

-8-6y+6y=3 yields

0=11 This result is not possible

Answer 3

Problem 1.
x-3y=4 and -2x+6y= 3 can be replaced by
-2x+6y=-8 and -2x+6y=3.
-2x+6y cannot be simultaniously -8 and 3.
So there is no solution.
In a graph you would see two // lines.

Problem 2 is the same kind of problem.

Answer 4

Problem 1.

2x+6y is double of x-3y
(dont consider the signs)
thus 8=3 not possible

Problem 2.
same methods

Answer 5

2*(x-3y=4) (2x-6y=8)
+
-2x+6y=3
=
0=11
IE no solution

2*(5x-y=3) (10x-2y=6)
+
-10x+2y=2
=
0=8
IE no solution

Answer 6

x - 3y = 4
-2x + 6y = 3

x - 3y = 4
-3y = -x + 4
y = (1/3)x - (4/3)

-2x + 6y = 3
6y = 2x + 3
y = (1/3)x + (1/2)

Since they both have the same slope and different y-intercepts, this problem has NO SOLUTION.

--------------------------------------------------

5x - y = 3
-10x + 2y = 2

5x - y = 3
-y = -5x + 3
y = 5x - 3

-10x + 2y = 2
2y = 10x + 2
y = 5x + 1

Again No Solution

Answer 7

x-3y=4
-2x+6y=3

2x-6y=8
-2x+6y=3

0x+0y=11
no solution for x & y because did not satisfy the equation

5x-y=3
-10x+2y=2

10x-2y=6
-10x+2y=2

0x+0y=8

again no solution for x & y because it did not satisfy the equation