Problem 1.
y+x=2
y+x=3
Problem 2.
x-5= y
y+2x= 0
2006-07-18 04:17:17 · 6 answers · asked by Brandon ツ 3 in Science & Mathematics ➔ Mathematics
Problem 1.
2=3 not possible.Thus no solution
Problem 2.
by substitution
x = 5/3 and y = - 10/3
2006-07-18 04:30:01 · answer #1 · answered by Anonymous · 2⤊ 2⤋
Problem one cannot be solved that cannot be a system, as x+y cannot be equal to both 2 and 3 that is impossible
second one sub eqn 1 into 2 x-5+2x=0
3x=5
x=5/3=1.667
y=5/3-5
y=-10/3=-3.333
2006-07-18 11:23:54 · answer #2 · answered by Aaron G 2 · 0⤊ 0⤋
problem one : no solutions
problem 2 : x = 5/3, y=-10/3
2006-07-18 11:22:23 · answer #3 · answered by gjmb1960 7 · 0⤊ 0⤋
y=2-x
x=3-y
prob2.x-5+2x=0,x=5,y=0
2006-07-18 11:38:47 · answer #4 · answered by anurag21 1 · 0⤊ 0⤋
y + x = 2
y + x = 3
y + x = -x + 2
y = -x + 3
No Solution
---------------------------------
x - 5 = y
y + 2x = 0
(x - 5) + 2x = 0
x - 5 + 2x = 0
3x - 5 = 0
3x = 5
x = (5/3)
(5/3) - 5 = y
(5/3) - (15/3) = y
(-10/3) = y
x = (5/3)
y = (-10/3)
2006-07-18 11:34:51 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
prob 2
y=-10/3
x=25/3
2006-07-18 11:22:45 · answer #6 · answered by Anniyan " follow the rules 1 · 0⤊ 0⤋