x2+y2=105
y2+x2=35
2006-07-18 03:43:37 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
There's no solution. You have 105 = 35, and that's false.
2006-07-18 03:49:13 · answer #1 · answered by bpiguy 7 · 0⤊ 0⤋
No. In fact, nobody should be able to solve it at all, using anything. Here's why:
if 105 = y2 + x2 = 35, then 105 would have to equal 35, which is impossible.
therefore, no solution.
2006-07-18 03:50:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋
If what you mean is x-squared and y-squared, as in:
x^2 + y^2 = 105
y^2 + x^2 = 35
then there are no solutions. Subtracting the 2nd equation from the first gives 0 = 70, which is naturally false.
Hope that's what you had in mind! :)
2006-07-18 03:54:14 · answer #3 · answered by Jay H 5 · 0⤊ 0⤋
105=35 or
21 = 7
never.
2006-07-18 04:38:53 · answer #4 · answered by Anonymous · 0⤊ 0⤋
it isnt possible...sorry... no matter how you break it down you simplify it out to 105=35... which is obviously not true
i.e.
x2 = 105-y2
plug into second equation
y2+105-y2=35
105=35... not true
2006-07-18 03:50:16 · answer #5 · answered by Calhoun 2 · 0⤊ 0⤋
There several solution. The basic one a unit circle with radius of one . the other is a circle whose radius is square root of 140.
2006-07-18 04:24:40 · answer #6 · answered by goring 6 · 0⤊ 0⤋
x^2 + y^2 = 105
y^2 + x^2 = 35
x^2 + y^2 = 105
x^2 + y^2 = 35
No Solution
2006-07-18 04:36:11 · answer #7 · answered by Sherman81 6 · 0⤊ 0⤋
it uses irrational and there's no real numbers!
2006-07-18 03:50:18 · answer #8 · answered by Anonymous · 0⤊ 0⤋
They aren't real numbers, so no, you cant.
2006-07-18 03:47:07 · answer #9 · answered by . 3 · 0⤊ 0⤋
NO
2006-07-18 03:51:48 · answer #10 · answered by dragonlady 4 · 0⤊ 0⤋