If the perimeter is 92 yards, then what are the length and width?
2006-07-18 03:27:12 · 13 answers · asked by Brandon ツ 3 in Science & Mathematics ➔ Mathematics
Best answer will be selected tomorrow!
2006-07-18 03:27:59 · update #1
l = w + 12
P = 2(L + W)
92 = 2((W + 12) + W)
92 = 2(W + 12 + W)
92 = 2(2W + 12)
92 = 4(W + 6)
23 = W + 6
W = 17
L = W + 12
L = 17 + 12
L = 29
Width = 17 yards
Length = 29 yards
2006-07-18 04:42:50 · answer #1 · answered by Sherman81 6 · 4⤊ 0⤋
If we designate w as the width in yards and l as the length in yards, then we know that...
--- w + l + w + l = 2w + 2l = 92 (as that's what a perimeter is)
--- w + l = 46
We also know that...
--- w + 12 = l (from the above information)
Substitute w+12 into l in the first equation...
--- w + (w + 12) = 46
--- 2w + 12 = 46
--- 2w = 34
--- w =17
The width is 17 yards, and the length would be 17+12 = 29 yards. If you really wanted to check it, you could punch 17+17+29+29 into a calculator and the answer would be 92.
2006-07-18 11:56:56 · answer #2 · answered by Kyrix 6 · 0⤊ 0⤋
Assume the width equals x. Then the length must be (x+12). Now since the perimeter is given as 92 yards, and we know that perimeter for a rectangle equals twice length + twice width, therefore 92 = 2x + 2(x+12).
Therefore, 92 = 4x + 24.
4x = 92-24 = 68.
Hence x = 68/4 = 17
So, the width is 17 yards, and the length is 17+12=29 yards.
2006-07-18 10:37:41 · answer #3 · answered by al 2 · 0⤊ 0⤋
since 2x +2y = Perimeter of a rectangle; (where x=width; y=length).
In this case y = x + 12;
substituting: 2x + 2(x+12) = 92yds;
2x + 2x + 24 = 92 yds;
4x + 24 = 92yds;
4x = 92-24;
4x = 68; therefore x = 68/4;
x = 17. y= 17 + 12. Therefore width is 17yds; length is 29yds.
2006-07-18 10:54:41 · answer #4 · answered by dollface 1 · 0⤊ 0⤋
Let W = width.
Then length = 12 + W.
Then perimeter = length+length+width+width=
92 = (12+W)+(12+W)+W+W.
92 = 24 + 4W
68 = 4W
W = 17
L= 29.
2006-07-18 10:33:17 · answer #5 · answered by fcas80 7 · 0⤊ 0⤋
W = L+12
P = 2(L + W) P=96
92 = 2 ( L + L + 12)
92 = 2( 2L+12)
92 = 4L + 24
92 - 24 = 4L
68 = 4 L
17 = L
17 + 12 = 29
SIDES ARE 29,29,17,17
2006-07-18 10:35:33 · answer #6 · answered by Brian D 5 · 0⤊ 0⤋
2(w+12) + 2w = 92
4w + 24 = 92
4w = 68
w = 17
mean L = w + 12 = 29
check: 17+17+29+29 = ? = 92 yep
2006-07-18 10:33:06 · answer #7 · answered by cw 3 · 0⤊ 0⤋
17 yards and 29 yards.
17*4 = 68 + 24 = 92
so
(17 * 2 ) + (29*2) = 92 yards
2006-07-18 10:31:53 · answer #8 · answered by BeC 4 · 0⤊ 0⤋
okay here's what we know: (x is length, y is width)
p = 92.
x = 12y
2x+2y = 92
solve it like a system...
2(12y) + 2y = 92
26y = 92
y = appx. 3.7
x = 12y so...
x = 12(3.7)
x = 44.4
so the length is 44.4 and the width is 3.7
hope this is right
UGH!!!!
now i see that i read the freaking problem wrong!!!
time wasted. oh well. some of the other answers might be right...
*checks high school report card to make sure there really is an a next to algebra*
*sigh*
2006-07-18 10:37:34 · answer #9 · answered by paralyzed nomad 3 · 0⤊ 0⤋
The length is 52 yds and the width is 40.
2006-07-18 10:32:27 · answer #10 · answered by tw0cl0n3m3 6 · 0⤊ 0⤋