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If 11,064,318 represents 52% of shares, what would 100% be? 48%?

2006-07-18 02:55:01 · 11 answers · asked by sahel578 5 in Science & Mathematics Mathematics

11 answers

100% = 21,277,535

48% = 10,213,217

2006-07-18 02:59:16 · answer #1 · answered by Anonymous · 3 1

11,064,318 = 52%
10,213,216 = 48%
21,277,534 = 100%

To find 100% (or 1 whole) = 11,064,318 x 100/52
[since 52/100 (or 52%) x 100/52 = 1]
Then find 48 percent = 21,277,534 x 48/100

2006-07-18 10:18:51 · answer #2 · answered by dollface 1 · 0 0

Let x equal the total number of shares (100%). Then, start with a proportion: 11,064,318/x = 52/100 and solve for x. Once you have the total number of shares, you can subtract the 11 million number from it, and you'll have the 48% of the shares.

2006-07-18 10:01:46 · answer #3 · answered by hcbiochem 7 · 0 0

divide 11,064,318 by 52 and multiply by 100 to get 100%
divide 11,064,318 by 52 and multiply by 48 to get 48%

2006-07-18 10:30:30 · answer #4 · answered by nuwanusa 5 · 0 0

100% = 21,277,534.61
48%= 10,213,216.61

11,064,318 divided by .52= 21,277,534.61 x .48=10,213,216.61

2006-07-18 10:18:50 · answer #5 · answered by ka5flm 2 · 0 0

11,064,318 is 52% of x, which in math symbols converts to:

11,064,318 = 0.52*x.

So x is the whole, or 100%, which is 11,064,318/0.52 = 21,277,534.6. The other 48% is what remains.

y = 0.48*21,277,534.6, so y=10,213,216.6.

2006-07-18 10:02:29 · answer #6 · answered by Cols 3 · 0 0

by using cross multiplication
-------------------------------------
for 100% ------> (11064318*100)/52
therfore 100% = 21277534.62

for 48% -------> (11064318*48)/52
therfore 48% = 10213216.62

i hope u got ur point from my explanation & i hope its the right answer

2006-07-18 10:06:37 · answer #7 · answered by Kevin 5 · 0 0

11064318 / 0.52 = 21277534.62 <-- 100%

21277534.62 * 0.48 = 10213216.62 <-- 48%

2006-07-18 10:04:50 · answer #8 · answered by Kyrix 6 · 0 0

That's a really easy problem. Just cross multiply.

2006-07-18 09:59:17 · answer #9 · answered by Anonymous · 0 0

difficult

2006-07-18 09:57:56 · answer #10 · answered by hanifrng 3 · 0 0

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