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2006-07-18 02:12:24 · 3 answers · asked by goring 6 in Science & Mathematics Physics

Calculations and proof?

2006-07-18 02:30:58 · update #1

3 answers

The force of gravity obeys the inverse-square law. That means, when you are twice as far away, the force of gravity is 1/4th as strong.

So, earth's gravitational pull on the moon is much stronger than the sun's gravitational pull because the moon is much much closer to the earth than the sun.

The moon is approx. 380,000 km (3.8 x 10^5) from earth.
The moon is approx. 150,000,000 km (1.5 x 10^8) from the sun.

So...

1/(3.8 x 10^5)^2 = 6.9 x 10^(-12)
1/(1.5 x 10^8)^2 = 4.4 x 10^(-17)

The graviational force the moon experiences from the earth is 5 orders of magnitude greater (100,000 times stronger) than what it experiences from the sun.

2006-07-18 02:32:02 · answer #1 · answered by Jared Z 3 · 1 0

Hey kid ask ur question properly to get a correct answer...anyways the gravitational pull of earth is greater than Sun over Moon understood that's why it does not deviate from it's path...

2006-07-18 02:26:46 · answer #2 · answered by Wolverine 3 · 0 0

It relies upon! If the moon were in it is modern orbit and unexpectedly had a more suitable pull to the solar for besides the actuality that reason, it may curve extra in the direction of the solar. notwithstanding it ought to also be in a strong orbit around the solar, only b/c it is extra huge would not recommend it immediately won't be able to orbit.

2016-10-14 22:17:15 · answer #3 · answered by ikeda 4 · 0 0

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