how to convert a 48% soln of caustic soda to 23%?

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how to convert a 48% soln of caustic soda to 23%?

2006-07-17 20:30:57 · 4 answers · asked by Ashiq S 1 in Science & Mathematics ➔ Chemistry

4 answers

Use the formula:

C1V1 = C2V2

Where C1 is the initial concentration (48%) and C2 is the final concentration (23%). V1 is in the initial volume and V2 is the final volume.

V2 - V1 = how much water you need to add to achieve the desired dilution

2006-07-18 10:53:24 · answer #1 · answered by niuchemist 6 · 0⤊ 0⤋

48% NaOH means 48 gm NaOH in 100 ml water

Let added water is x ml to convert 48% NaOH into 23% NaOH

then 48/(100+x)=23/100
100+x=48*100/23
x=108.69

2006-07-18 05:16:49 · answer #2 · answered by August 2 · 0⤊ 0⤋

Just add water

2006-07-18 04:40:48 · answer #3 · answered by puppy 3 · 0⤊ 0⤋

add 108.69 more units of water.

2006-07-18 03:36:59 · answer #4 · answered by klamath 2 · 0⤊ 0⤋