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10 answers

if you can't figure that out, go back to school

2006-07-17 17:01:44 · answer #1 · answered by Comfortably Numb™ 7 · 0 0

do your own darn homework, divide how much it cost by how many pounds to get cost per pound. if she had spent $6 for 3 pounds, $6 divided by 3 =$2 per pound, so take your $5.23 and divide it by the 3.6 pounds to figure out her cost per pound. have fun, and then go figure out your mom's gas mileage...

aunt crylllie

2006-07-17 17:05:20 · answer #2 · answered by cryllie 6 · 0 0

Total amt paid = 5.23 for 3.6 pounds

:. per pound = 5.23/3.6=1.45

2006-07-17 17:22:16 · answer #3 · answered by jv 2 · 0 0

hi! watch.. finished bill = 30 kilos / 3 people = 10 kilos each Waiter returns with 5 kilos substitute, meaning they paid 25 kilos finished (30 kilos - 25 kilos = 5 kilos) 25 kilos / 3 people = 8.33333 kilos each so as meaning they spent 8 kilos and 33 'cents' (33/one hundred part of a pound) and they each supply the waiter a a million pound tip so 8.33333 + a million = 9.33333 kilos each. 3 people * 9.33333 kilos = 28 kilos and they are left with 2 kilos... "the position is the lacking a million pound"??? nicely the mistakes changed into you stated they each pay 9 kilos each, they payed 9 kilos and 33 cents each. desire that helped!

2016-10-14 22:06:52 · answer #4 · answered by ? 4 · 0 0

Take the amount she paid, 5.23, and divide it by 3.6. From therse you can find out how much one pund cost.

2006-07-17 17:11:19 · answer #5 · answered by bunches999 4 · 0 0

5.23 divided by 3.6 will give you the amount per pound.

2006-07-17 17:01:04 · answer #6 · answered by Mariposa 7 · 0 0

$5.23 cost / 3.6 pounds = $1.45 per pound

2006-07-17 17:10:43 · answer #7 · answered by taceysay02@sbcglobal.net 3 · 0 0

5.23 = 3.6(x)


1.45 per lb

check

1.45 x 3.6 = 5.23

2006-07-17 17:01:26 · answer #8 · answered by Yentl 4 · 0 0

$5.23 / 3.6 lbs = $1.45/lb (roughly)

2006-07-17 17:01:57 · answer #9 · answered by jihad_against_muslims 3 · 0 0

1.452777777777

2006-07-17 17:03:20 · answer #10 · answered by Ashok k 1 · 0 0

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