(a^3/7 x b^-2/5)^3?

5 ⤊

Evaluate express answer using only positive exponents.

2006-07-17 16:36:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

multiply the three by both exponents inside the parentheses, to get:
(a^9/7 x b^ -6/5)

then to make the b exponent positive, flip it down below the fraction bar, to get:

(a^9/7) / (b^6/5)

good luck

2006-07-17 17:17:40 · answer #1 · answered by smm9909 1 · 5⤊ 2⤋

(a^9/7)/(b^6/5) or (a^9/7)*(b^-6/5)

2006-07-18 02:52:24 · answer #2 · answered by ss 2 · 0⤊ 0⤋

(a^(9/7))/(b^(6/5))

2006-07-17 16:39:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋

((a^(3/7)) * (b^(-2/5)))^3

a^((3/7) * 3) * b^((-2/5) * 3)

a^(9/7) * b^(-6/5)

(a^(9/7))/(b^(6/5))

2006-07-18 02:10:53 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋