2006-07-17 09:59:46 · 5 answers · asked by inhisgrip4eva 1 in Science & Mathematics ➔ Mathematics
f(k)=k+5 which is an even number
f(k+5)=(k+5)/2
f(k+5)=25
k+5=25*2
k=45
4+5=9
2006-07-17 10:11:18 · answer #1 · answered by lavi_or_lavinia 2 · 0⤊ 0⤋
f(25) would be 30 (since 25 is an odd number). f(30) would be 15 (since 30 is an even number). The sum of those 2 numbers would be 45.
2006-07-17 17:04:06 · answer #2 · answered by mthtchr05 5 · 0⤊ 0⤋
I don't like to do complete problems, only to get you started in the right direction. But with this one, maybe we have to go all the way.
Since k is odd, f(k) = k + 5. When you add two odd numbers, k and 5, the result, f(k), is even.
Therefore, f(f(k)) = f(k)/2 = (k + 5)/2 = 25.
Solve that last equation for k, and add its two digits together to get your answer.
2006-07-17 17:11:57 · answer #3 · answered by bpiguy 7 · 0⤊ 0⤋
sum of two K's can be 2 or -2 --> 1(1(25))
2006-07-17 17:10:31 · answer #4 · answered by chase 2 · 0⤊ 0⤋
k=2m+1 then:
f(2m+1)=2m+6 then:
f(2m+6)=m+3=25
m=22 And:
k=2(22)+1=45
sum of digit: 9
2006-07-17 17:26:41 · answer #5 · answered by fumani55 2 · 0⤊ 0⤋