Since there are a large number of rolls, I would suggest using the normal approximation, since the Central Limit Theorem would apply. On an average roll, you would expect to get (1+2+3+4+5+6)/6 = 3.5, and the SD of 1, 2, 3, 4, 5, and 6 would be 1.87. So, if we look at the sum of 200 rolls, we would expect a sum of 200*3.5 = 700 with an SD equal to the standard error, which is sqrt(200)*1.87 = 26.46. It would take many standard errors to get to 1194 (over 18), so the probability would be very close to zero.
2006-07-17 10:40:01
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answer #1
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answered by blahb31 6
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Very very low. You'd have to get 194 sixes and 6 fives, 195 sixes and 6 fours, 196 sixes and 6 threes, 197 sixes and 6 twos, 198 sixes and 6 ones, 197 sixes and 3 fours, and maybe there are some others. I'm not sure. So this is like 6 out of 1194 (since the lowest the 200 dice can add up to is 6 and the highest is 1200), or 1/199.
2006-07-17 16:40:05
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answer #2
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answered by Anonymous
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Exactly 11570476970884000 chances in 6^200, or:
2.7108231485352901102440625417357 x 10^-140
2006-07-17 20:11:29
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answer #3
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answered by Keith P 7
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That isnt really helpful to you or anyone else, get outside and take in some fresh air/ some sun!!!!
2006-07-17 16:19:52
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answer #4
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answered by David 1
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What is the probability that anyone cares?
2006-07-17 16:17:48
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answer #5
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answered by quietwalker 5
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approx. zero
2006-07-17 17:35:58
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answer #6
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answered by cw 3
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at least this guy TRIED to disguise his homework as something he was interested in. thanks for the effort.
2006-07-17 16:27:50
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answer #7
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answered by twinsfan 2
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12.00000000000000192%
2006-07-17 16:29:47
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answer #8
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answered by default 3
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