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a dice has six sides is rolled two hundred times what is the problity that sum of all
rolls numbers equals 1194?

2006-07-17 09:15:05 · 8 answers · asked by mohamed.kapci 3 in Science & Mathematics Mathematics

8 answers

Since there are a large number of rolls, I would suggest using the normal approximation, since the Central Limit Theorem would apply. On an average roll, you would expect to get (1+2+3+4+5+6)/6 = 3.5, and the SD of 1, 2, 3, 4, 5, and 6 would be 1.87. So, if we look at the sum of 200 rolls, we would expect a sum of 200*3.5 = 700 with an SD equal to the standard error, which is sqrt(200)*1.87 = 26.46. It would take many standard errors to get to 1194 (over 18), so the probability would be very close to zero.

2006-07-17 10:40:01 · answer #1 · answered by blahb31 6 · 0 0

Very very low. You'd have to get 194 sixes and 6 fives, 195 sixes and 6 fours, 196 sixes and 6 threes, 197 sixes and 6 twos, 198 sixes and 6 ones, 197 sixes and 3 fours, and maybe there are some others. I'm not sure. So this is like 6 out of 1194 (since the lowest the 200 dice can add up to is 6 and the highest is 1200), or 1/199.

2006-07-17 16:40:05 · answer #2 · answered by Anonymous · 0 0

Exactly 11570476970884000 chances in 6^200, or:

2.7108231485352901102440625417357 x 10^-140

2006-07-17 20:11:29 · answer #3 · answered by Keith P 7 · 0 0

That isnt really helpful to you or anyone else, get outside and take in some fresh air/ some sun!!!!

2006-07-17 16:19:52 · answer #4 · answered by David 1 · 0 0

What is the probability that anyone cares?

2006-07-17 16:17:48 · answer #5 · answered by quietwalker 5 · 0 0

approx. zero

2006-07-17 17:35:58 · answer #6 · answered by cw 3 · 0 0

at least this guy TRIED to disguise his homework as something he was interested in. thanks for the effort.

2006-07-17 16:27:50 · answer #7 · answered by twinsfan 2 · 0 0

12.00000000000000192%

2006-07-17 16:29:47 · answer #8 · answered by default 3 · 0 0

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