How many different amounts of money might we get?
2006-07-17 08:22:33 · 9 answers · asked by retrodaisy1 1 in Science & Mathematics ➔ Mathematics
I believe this is a combination question not a monetary value question. ie... how many different combinations can I get ?
2006-07-17 08:42:26 · update #1
243. for each draw, you could theorhetically get either a nickel, a penny, or a quarter. if you have three options for each draw it's 3*3*3*3*3.
I think.
NO. I take that back, because drawing
P P N P P
yields the same amount as
N P P P P,
It actually comes down to 21 distinct amounts:
0.05, 0.09, 0.13, 0.17, 0.21, 0.25, 0.29, 0.33, 0.37, 0.41, 0.45, 0.53, 0.57, 0.61, 0.65, 0.77, 0.81, 0.85, 1.01, 1.05, 1.25
2006-07-17 08:28:13 · answer #1 · answered by heather-mpc@sbcglobal.net 2 · 0⤊ 0⤋
In cents (with pennies-nickels-quarters):
5 (5-0-0)
9 (4-1-0)
13 (3-2-0)
17 (2-3-0)
21 (1-4-0)
25 (0-5-0)
29 (4-0-1)
33 (3-1-1)
37 (2-2-1)
41 (1-3-1)
45 (0-4-1)
53 (3-0-2)
57 (2-1-2)
61 (1-2-2)
65 (0-3-2)
77 (2-0-3)
81 (1-1-3)
85 (0-2-3)
101 (1-0-4)
105 (0-1-4)
125 (0-0-5)
2006-07-17 08:44:35 · answer #2 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋
fifty seven quarters and 40 3 dimes. it is that if a dime is 10 cents suitable? i'm english :S besides yeh only cases the ten cents with the aid of one hundred and you have 10$. then you definately've 8.fifty 5 left over to make up with the 25 cents. the version between the two funds is 15 cents so, 8.fifty 5 divided with the aid of 15 is 0.fifty seven. meaning you want fifty seven of the 15's extra to make the extra beneficial 8.fifty 5. Does that make experience lol? i will attempt back to describe
2016-11-02 05:42:21 · answer #3 · answered by garion 4 · 0⤊ 0⤋
243 is too many, because the least you could have is 5 cents the most is $1.25 that leaves only 120 possible, but it isn't even that many.
120 is too many because you cannot get .06, .07, .08 c what i mean?
I believe the correct answer is 21 different combinations.
2006-07-17 08:33:23 · answer #4 · answered by Scott M 3 · 0⤊ 0⤋
120
5*4*3*2*1
You know it has to be less than 125 (the value of 5 quarters)
Oops, Heather is correct, the 5! formula I used is for making sure no repeats occurred, not appropriate for the question.
2006-07-17 08:31:54 · answer #5 · answered by MikeInTally 1 · 0⤊ 0⤋
3^3
27 different combinations
ranging from 3 cents to 75 cents
2006-07-17 08:30:26 · answer #6 · answered by jasonalwaysready 4 · 0⤊ 0⤋
If you're not sure what the teacher wanted as an answer, why not ask them first . Then, when you get someone to answer your homework at least you can pretend you got it right.
If it helps, there are some lovely wrong answers here.
2006-07-17 08:44:15 · answer #7 · answered by Anonymous · 0⤊ 0⤋
You could get 21 amounts
$1.25
$1.05
$1.01
$0.85
$0.81
$0.77
$0.65
$0.61
$0.57
$0.53
$0.45
$0.41
$0.37
$0.33
$0.29
$0.25
$0.21
$0.17
$0.13
$0.09
$0.05
2006-07-17 08:43:49 · answer #8 · answered by jimbob 6 · 0⤊ 0⤋
i dont no
2006-07-17 08:26:00 · answer #9 · answered by Anonymous · 0⤊ 0⤋