possible restriction map for a circular plasmid?

Question

possible restriction map for a circular plasmid

Restriction Enzyme Fragment Size (kb)
EcoRI 4.0
HaeII 1.6, 2.4
PstI 1.9, 2.1
EcoRI and HaeII 0.7, 1.6, 1.7
EcoRI and PstI 0.8, 1.3, 1.9
HaeII and PstI 0.6, 0.9, 1.0, 1.5

construct the possible restriction map for teh circular plasmid from the data...

Answer 1

Well I found two possible maps; maybe I am missing something and one of them is wrong:

You have a circular plasmid and EcoRI gives a single fragment of 4 Kb. Thus EcoR I cuts only once and the total size of your plasmid is 4.0 kb.
We assume that EcoRI is at the beginning of the sequence for simplicity.

HaeII gives two fragments thus it cuts the plasmid twice. Since the combination of EcoRI and HaeII gives three fragments and one has the same size as when HaeII cuts alone (1.6 kb) the site of EcoRI should be in the 2.4 kb fragment that is generated when HaeII cuts alone.
So since we chose EcorI as the start of the sequence you either have HaeII at -1.7kb and +0.7kb of at -0.7kb and +1.7kb.

The same reasoning applies for PstI and you get that PstI sites should be either at -0.8kb and +1.3 kb or at -1.3kb and +0.8kb.

From the 4 possible combinations two of them are possible so that they give the correct fragments with the HaeII & PstI combination:

1) -1700 HaeII -800 PstI 1 EcoRI 700 HaeII 1300 PstI or more correctly written:
1 EcoRI 700 HaeII 1300 PstI 2300 HaeII 3200 PstI

2)1 EcoR I 800 PstI 1700 HaeII 2700 PstI 3300 HaeII
(-1300 PstI -700 HaeII 1 EcorI 800 PstI 1700 HaeII)

Answer 2

who do you except to draw you this picture?

Answer 3

yeah so what's your question?