x^2 + 3xy -5wx -15wy
x(x+3y) - 5w(x+3y)
(x-5w)(x+3y)
2006-07-17 05:58:45
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answer #1
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answered by jimvalentinojr 6
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Combine like terms first:
x^2 + 3xy - 15wy - 5wx.
x(x + 3y) - 5w(3y + x)
(x - 5w)(x + 3y) = answer
2006-07-17 06:00:56
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answer #2
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answered by thunderbomb90 3
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Making my head spin...
There is no variable that can be taken out right away...
(x^2+3xy)+(-15wy-5wx)?
= x(x+3y) - 5w(3y+x)
= (x+5w)(x+3y)
I can only get you that far, don't know if it's right or not...
2006-07-17 06:03:01
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answer #3
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answered by Anonymous
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looks like (x-5w)(x+3y) to me. But I haven't done these in a while so I might be wrong
2006-07-17 05:59:10
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answer #4
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answered by Tikhacoffee/MisterMoo 6
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X^2+3XY-15WY-5WX
X(X+3Y)-5W(3Y+X)
(X-5W)(X+3Y)
I am pertty sure that is the correct answer
2006-07-17 06:06:13
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answer #5
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answered by ika 2
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x^2-15wy+3xy-5wx
x^2-5wx-15wy+3xy
x(x-5w)+3y(-5w+x)
x(x-5w)+3y(x-5w)
(x-5w)(x+3y)
Factor by grouping like terms.
2006-07-17 06:01:15
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answer #6
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answered by powhound 7
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x^2-15wy+ x(3y-5w) i forgot the rest
2006-07-17 06:04:46
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answer #7
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answered by bigbruth 2
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x^2-15wy-5wx+3xy
x^2 -5w(3y+5x) + 3xy
x^2 + 3xy -5w(3y+5x)
x(x+3y) -5w(3y+ 5x)=0
x(x+3y)= 5w(3y+5x)
x/5w= 5x+3y/x+3y
x=5w(5x+3y/x+3y)
2006-07-17 06:31:20
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answer #8
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answered by thewordofgodisjesus 5
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Trust me. Its like this...
(x^2)-5*(wx+3*(wy-0.2*xy))
The * symbol means multiply. I ran this through my TI-89 and it works. Good luck.
2006-07-17 06:12:21
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answer #9
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answered by Qcaz 1
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= x[x+3y]-5w[x+3y]
= [x-5w][x+3y]
2006-07-17 05:59:08
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answer #10
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answered by Anonymous
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