2006-07-17 05:41:08 · 8 answers · asked by cityturtleblue 2 in Science & Mathematics ➔ Mathematics
(3X-6Y)(3X+6Y)
2006-07-17 05:46:03 · answer #1 · answered by vdubberus 2 · 0⤊ 0⤋
9x^2-36y^2 = (3x)^2-(6y)^2 = (3x - 6y)(3x+6y) ,
by difference of perfect squares.
(3x-6y) = 3(x-2y) and (3x+6y) =3(x+2y).
Therefore, the answer is = 3(x-2y) 3(x+2y) = 9(x-2y)(x+2y).
2006-07-17 14:35:43 · answer #2 · answered by StreetX 2 · 0⤊ 0⤋
9x^2 - 36y^2
9(x^2 - 4y^2)
9(x - 2y)(x + 2y)
2006-07-17 16:30:30 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
This is a difference of squares....which you should probably memorize if possible (3x-6y)(3x+6y)
A^2-B^2 = (A-B)(A+B)
2006-07-17 13:07:06 · answer #4 · answered by CHAZ2006 3 · 0⤊ 0⤋
(3x+6y)*(3x-6y) = 9x^2-36y^2
2006-07-17 12:47:12 · answer #5 · answered by AresIV 4 · 0⤊ 0⤋
hmmm... ok.. first factor out the 9
9(x^2-4y^2)
now.. break 9 down into it's prime factors...
3*3(x^2-4y^2)
now... factor x^2-4y^2... hmmm... (x + 2y)(x-2y)
3*3*(x+2y)*(x-2y)
2006-07-17 12:47:19 · answer #6 · answered by ♥Tom♥ 6 · 0⤊ 0⤋
Uh, those people are right... (3x+6y)(3x-6y) is the right answer...
2006-07-17 12:52:27 · answer #7 · answered by Anonymous · 0⤊ 0⤋
^g0`0u+s1de^
2006-07-17 12:45:10 · answer #8 · answered by ♣ 4 · 0⤊ 0⤋