What are the chances that one will lose eight times in a row in roulette if they switched colors every time?

Question

i mean, if i bet red then black then red then black then red...and so on, switching colours every time, what are the chances that i will lose all eight in a row. i know it is very complecated, but there are some very smart people on this site!!

PS: lets say on a europian table!

Answer 1

Your switching doesn't affect each individual round. So the odds don't change whether you stay on 1 color or switch (assuming you don't go to the zero)

In European roulette, you have 37 numbers. Red and Black are 18/37, and one zero.

So, from round to round your odds of losing are equal 19/37.

But, if you're asking, "prior to starting, what are my odds of losing 8 in a row?"

Then it is (19/37)^8=.0048
Or, 48 times in 10000 tries, as long as there is no "fix".

Answer 2

1 in 256. Each time, you have a 50% chance of winning, regardless of whether or not you switch colors. Your odds of losing each time should be 1 divided by 2^8. If you spin once, your odds of losing once (100% of the time) are 1/2. If you spin twice, your odds of losing twice are 1/4. Three times is 1/8. Eight times calculates to 1/256. I'm assuming (see correction below) that there are an equal number of black and red numbers, and that all numbers are either black or red.
CORRECTION: Iridium190 is correct. Since there are is also the 37th number, 0, which is neither red nor black, the probability of losing each time is 19/37, not 1/2. This equates to 0.4835%

Answer 3

1 chance in 256

It matters not that you've changed colors along the way. There is a 50/50 chance of losing each time.

The answer is 1/2 if you play once. To lose two times in a row, it is 1/4...so 1 / (2) ^8 is 1/256

Answer 4

100 to 1

Answer 5

Switching colors matters not in the least - you have an equal chance of losing on each spin of the wheel, because each spin is an independent event unrelated to any previous spin.

The chance of losing on one spin of the wheel is 19/37. The chance of losing twice is (19/37)^2. The chance of losing eight times in a row is (19/37)^8, or about 0.31%.

In other words, it is almost unheard of to lose an even-money bet on a European roulette wheel eight times in a row.

Answer 6

Slightly better than 50/50 depending on whether the wheel has only the single zeo or the double zero as well, and swithching colors makes no difference.

Answer 7

50/50 is wrong, you have to put the 0/00 in play. Roulette is 100% random, there are no patterns, only luck

Answer 8

The chances of loosing each time are slightly greater than 50%. The string has nothing inherent in the equation.

Answer 9

1 in 2^8 = 0.00390625

Oops, I forgot the 0...

(19/37)^8, or (20/38)^8 if you have the 00 piece.

Answer 10

THE SAME AS WINNING 8 TIMES IN A ROW. COLOR DOESN'T COUNT