On a European roulette wheel, there are 37 spaces (18 black, 18 red, and 1 green). Therefore, the odds of getting the same color (black/red) eight times in a row is 18^8 times in 37^8, which is 11,019,960,576 times in every 3,512,479,453,921, which works out to be about 0.31% of the time, which is about once out of every 319 occurances.
The odds of getting green 8 times in a row on a European roulette wheel are one in every 3,512,479,453,921.
The odds change significantly if you play American Roulette instead. An American Roulette wheel has two green spaces instead of one (0 and 00). There are a total of 38 spots on an American roulette wheel. Therefore, the odds of getting black or red eight times in a row are 18^8 times out of every 38^8 times. This means that it will occur 11,019,960,576 times out of every 4,347,792,138,496, which is about 0.25% of the time, or about one time out of every 395 instances.
The odds of getting eight greens in a row in American roulette are 256 times out of every 4,347,792,148,496, or once out of every 16,983,563,080 times.
2006-07-17 05:10:51
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answer #1
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answered by Anonymous
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Each spin is slightly less than 1 in 2 due to the 0 and 00 used on some Roulette wheels. You didn't state whether or not it was a 0 wheel or a 0 + 00 wheel, so we can't give you an exact answer.
But, if you use the chances being about 1 in 2, then the chance is 1 in 2^8 (2 to the 8th power), which is 1 in 256.
2006-07-17 04:55:26
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answer #2
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answered by Anonymous
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The odds never change it is a 50/50 chance that any color will come up any time for example it is 50/50 that 100 reds will come in a row or its 50/50 that 2 reds will come in a row
2006-07-17 04:54:42
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answer #3
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answered by Chris4320 1
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If you have 36 numbers + Green 0 then
For 8 greens in a row it's (1/37)^8 = 3,512,479,453,921 : 1
For Red or Black: 36/37 * (18/37)^7 = 159 :1
2006-07-17 04:58:54
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answer #4
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answered by Grant d 4
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There are 18 red, 18 black, and 2 green slots on a roulette wheel.
The probability of getting red once is 9/19.
The probability of getting red eight times consecutively is (9/19)^8.
(9/19)^8 = approx. 0.00253461, or about once in every 395 tries.
The probability of getting black eight times consecutively is also (9/19)^8.
The probability of getting green eight times consecutively is (1/19)^8, which is incredibly miniscule.
The probability of getting the same color eight times in a row is approx. 0.00507, or about once in every 197 tries.
2006-07-17 04:56:20
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answer #5
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answered by Anonymous
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On a single-zero wheel, the probability that red will come up is .486486486... (that's 18/37)
The probability that red will come up eight times in a row is (.486486486...)^8 = .00313737, or one in every 318.74 trials.
On a double-zero wheel, tha probability that red will come up eight times in a row is .00253461, or one in every 394.54 trials.
2006-07-17 05:48:00
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answer #6
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answered by jimbob 6
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1 out of 2 to the eigth power = 1 in 256.
2006-07-17 04:53:38
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answer #7
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answered by Rjmail 5
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Roulette is a game of independent trials. The chance of hitting red or black is always 47.37% in a double-zero game.
2006-07-17 04:58:39
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answer #8
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answered by galactic_man_of_leisure 4
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What is that number ? 10 billion ? Yes I would do it. In fact you may have just come up with a great idea for a game show. I'd watch it.
2016-03-26 21:36:02
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answer #9
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answered by Janet 4
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