2006-07-16 20:17:05 · 17 answers · asked by moonnightsoar 2 in Science & Mathematics ➔ Mathematics
each number can be repeated up to three times exanple: 000, 001. 011. 101. ect.
2006-07-16 20:24:13 · update #1
10 * 10 * 10 = 1000 allowing repetition or
10 * 9 * 8 = 720 not allowing repetition
2006-07-16 20:21:47 · answer #1 · answered by bogusman82 5 · 0⤊ 0⤋
Since repetition has been allowed and obviously a number may start with a zero, the number of combinations is 10^3 = 1000.
2006-07-17 06:31:01 · answer #2 · answered by Thermo 6 · 0⤊ 0⤋
If repetition of digits is allowed then
first digit -> 10 ways
second -> 10 ways
third -> 10 ways
so total cominations = 10^3 = 1000
2006-07-17 04:18:18 · answer #3 · answered by amit 1 · 0⤊ 0⤋
1000 numbers 0-999
2006-07-17 03:22:52 · answer #4 · answered by Tim J 2 · 0⤊ 0⤋
The answer is 720 without repetition. Mathematical expression is 10 factorial divided by 7 factorial. i.e. 10!/7! = 3628800/5040 = 720
2006-07-17 04:05:22 · answer #5 · answered by vrajgokhlay 1 · 0⤊ 0⤋
You have 3 slots:
[_][_][_]
The first slot has 10 possibilities (0-9), the second slot has 10 possibilities (0-9) and the 3rd slot has 10 possibilities (0-9).
Therefore,
10 x 10 x 10 = 1000 combinations.
2006-07-17 05:39:14 · answer #6 · answered by ideaquest 7 · 0⤊ 0⤋
10 numbers taken 3 at a time with repititions allowed :
(10+3-1)!/3!(10-1)! = 12!/3!9! = 220
10 numbers taken 3 at a time with no repititions allowed :
10!/(10-3)!3! = 120.
2006-07-17 04:25:24 · answer #7 · answered by coolzadar 2 · 0⤊ 0⤋
900
2006-07-17 03:21:17 · answer #8 · answered by Lee J 4 · 0⤊ 0⤋
10^3 is how amny which is 1000.
2006-07-17 03:22:09 · answer #9 · answered by chevyman502 4 · 0⤊ 0⤋
100 to 999 is the answer for your question.
2006-07-17 03:23:45 · answer #10 · answered by sshhrini 2 · 0⤊ 0⤋